MHT CET 2021 21th September Evening Shift | Fluid Mechanics Question 60 | Physics

A big water drop is divided into 8 equal droplets. $$\Delta \mathrm{P}_{\mathrm{s}}$$ and $$\Delta \mathrm{P}_{\mathrm{B}}$$ be the excess pressure inside a smaller and bigger drop respectively. The relation between $$\Delta \mathrm{P}_{\mathrm{s}}$$ and $$\Delta \mathrm{P}_{\mathrm{B}}$$ is

$$\Delta P_B=\Delta P_S$$

$$\Delta \mathrm{P}_{\mathrm{B}}=\frac{1}{2} \Delta \mathrm{P}_{\mathrm{S}}$$

$$\Delta P_B=\frac{1}{4} \Delta P_S$$

$$\Delta P_B=2 \Delta P_S$$

MHT CET 2021 21th September Morning Shift

MCQ (Single Correct Answer)

-0

The surface tension of most of the liquid decreases with rise in

viscosity of the liquid

diameter of capillary

temperature of the liquid

density of the liquid

MHT CET 2021 21th September Morning Shift

MCQ (Single Correct Answer)

-0

The velocity of a small ball of mass '$$M$$' and density '$$\mathrm{d}_1$$' when dropped in a container filled with glycerine becomes constant after some time. If the density of glycerine is '$$\mathrm{d}_2$$', the viscous force acting on the ball is ( $$\mathrm{g}=$$ acceleration due to gravity)

$$\mathrm{Mg} \frac{\mathrm{d}_1}{\mathrm{~d}_2}$$

$$\mathrm{Mgd}_1 \mathrm{~d}_2$$

$$\operatorname{Mg}\left(d_1-d_2\right)$$

$$\operatorname{Mg}\left(1-\frac{\mathrm{d}_2}{\mathrm{~d}_1}\right)$$

MHT CET 2021 21th September Morning Shift

MCQ (Single Correct Answer)

-0

Two small drops of mercury each of radius '$$R$$' coalesce to form a large single drop. The ratio of the total surface energies before and after the change is

$$\sqrt{2}: 1$$

$$2^{2 / 3}: 1$$

$$2^{1 / 3}: 1$$

$$2: 1$$

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