1
GATE ECE 2000
MCQ (More than One Correct Answer)
+1
-0.3
For the logic circuit shown in Figure, the required input condition (A, B, C) to make the output (X)=1. GATE ECE 2000 Digital Circuits - Logic Gates Question 26 English
A
1, 0, 1
B
0, 0, 1
C
1, 1, 1
D
0, 1, 1
2
GATE ECE 2000
MCQ (Single Correct Answer)
+2
-0.6
For the logic circuit shown in the figure, the simplified Boolean expression for the output Y is GATE ECE 2000 Digital Circuits - Logic Gates Question 14 English
A
A + B + C
B
A
C
B
D
C
3
GATE ECE 2000
Subjective
+5
-0
The operating conditions (ON = 1, OFF = 0) of three pumps (x,y,z) are to be monitored. x = 1 implies that pump X is on. It is required that the indicator (LED) on the panel should glow when a majority of the pumps fail. GATE ECE 2000 Digital Circuits - Logic Gates Question 4 English

(a) Enter the logical values in the K-map in the format shown in figure 3(a). Derive the minimal Boolean sum-of-products expression whose output is zero when a majority of the pumps fail.
(b) The above expression is implemented using logic gates, and point P is the output of this circuit, as shown in figure 3(b). P is at 0 V when a majority of the pumps fails and is at 5 V otherwise. Design a circuit to drive the LED using this output. The current through the LED should be 10 mA and the voltage drop across it is 1V. Assume that P can source or sink 10 mA and a 5 V supply is available.

4
GATE ECE 2000
MCQ (Single Correct Answer)
+2
-0.6
A sequential circuit using D flip-flop and logic gates is shown in the figure, where X and Y are the inputs and Z is the output. The circuit is GATE ECE 2000 Digital Circuits - Sequential Circuits Question 42 English
A
S–R Flip-Flop with inputs X = R and Y = S
B
S–R Flip-Flop with inputs X = S and Y = R
C
J–K Flip-Flop with inputs X = J and Y = K
D
J–K Flip-Flop with inputs X = K and Y = J
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