1
GATE ECE 1999
MCQ (Single Correct Answer)
+1
-0.3
The input to a channel is a band pass signal. It is obtained by linearly modulating a sinusoidal carrier with a signal- tone signal. The output of the channel due to this input is given by y(t) = (1/100) cos$$(100t - {10^{ - 6}})\,$$ cos$$({10^6}t - 1.56)$$. The group delay $$({t_g})$$ and the phase delay $$({t_p})$$, in seconds, of the channel are
A
$${t_g} = {10^{ - 6}},\,{t_p} = 1.56$$
B
$${t_g} = 1.56,\,\,{t_p} = {10^{ - 6}}$$
C
$${t_g} = \,\,{10^{ - 8}},\,\,{t_p} = 1.56 \times {10^{ - 6}}$$
D
$${t_g} = {10^{ - 8}},\,{t_p} = 1.56$$
2
GATE ECE 1999
MCQ (Single Correct Answer)
+2
-0.6
The input to a matched filter is given by $$s(t) = \left\{ {\matrix{ {10\sin (2\pi \times {{10}^6}t),} & {0 < \left| t \right| < {{10}^{ - 4}}\sec } \cr 0 & {Otherwise} \cr } } \right.$$

The peak amplitude of the filter output is

A
10 Volts
B
5 Volts
C
10 millivolts
D
5 millivolts
3
GATE ECE 1999
MCQ (Single Correct Answer)
+2
-0.6
The Nyquist sampling frequency (in Hz) of a signal given by $$16 \times {10^{4\,}}\,\sin {c^2}(400t)*{10^6}\,\sin {c^3}(100t)$$ is
A
200
B
300
C
500
D
1000
EXAM MAP
Medical
NEETAIIMS
Graduate Aptitude Test in Engineering
GATE CSEGATE ECEGATE EEGATE MEGATE CEGATE PIGATE IN
Civil Services
UPSC Civil Service
Defence
NDA
Staff Selection Commission
SSC CGL Tier I
CBSE
Class 12