1
GATE ECE 1999
MCQ (Single Correct Answer)
+1
-0.3
The Logical expression $$Y = A + \overline A B$$ is equivalent to
A
y = AB
B
y = $$\overline A $$ B
C
y = $$\overline A $$ + B
D
y = A + B
2
GATE ECE 1999
MCQ (Single Correct Answer)
+2
-0.6
For a binary half-subtractor having two inputs A and B, the correct set of Logical expressions for the output D(=Aminus B) and X(=Borrow) are
A
D = AB + $$\overline A B,X = \overline A B$$
B
$$D = \,\overline A B + A\overline B + A\overline B , X= A\overline B $$
C
$$D = \overline A B + A\overline B ,X = \overline A B$$
D
$$D = AB + \overline A \,\overline {\,B} ,X = A\overline B $$
3
GATE ECE 1999
MCQ (Single Correct Answer)
+2
-0.6
The minimized form of the logical expression ($$\overline A \,\overline B \,\overline C + B\overline C + \overline A B\overline C + \overline A BC + AB\overline C )$$
A
$$\overline A \overline C + B\overline C + \overline A B$$
B
$$A\overline C + \overline B C + \overline A B$$
C
$$\overline A C + \overline B C + \overline A B$$
D
$$A\overline C + \overline B C + A\overline B $$
4
GATE ECE 1999
Subjective
+5
-0
In certain application, four inputs A, B, C, D (both true and complement forms available)are fed to logic circuit, producing an output F which operates a relay. The relay turns on when F(ABCD)=1 for the following states of the inputs (ABCD):'0000', '0010' ,0101',0110','1101' and '1110'. States '1000' and '1001' do not occur, and for the remaining states, the relay is off. Minaining states, the relay is off. Minimize F with the help of a Karnaugh map and realize it using a minimum number of 3- input NAND gates.
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