According to Kohlrausch’s law, the equivalent conductance of BaCl₂ at infinite dilution,

$$\lambda $$_{$$\infty $$} of BaCl₂ = $${1 \over 2}$$$$\lambda $$_{$$\infty $$} of Ba²⁺ + $$\lambda $$_{$$\infty $$} of Cl^-

$$ \Rightarrow $$ $$\lambda $$_{$$\infty $$} of BaCl₂ = $${1 \over 2} \times 127 + 76$$ = 139 5