MHT CET 2020 16th October Morning Shift | Magnetism and Matter Question 45 | Physics

Two identical bar magnets each of magnetic moment $$M$$, separated by some distance are kept perpendicular to each other. The magnetic induction at a point at the same distance $$d$$ from the centre of magnets, is ($$\mu_0=$$ permeability of free space)

$$\frac{\mu_0}{4 \pi}(\sqrt{3}) \frac{M}{d^3}$$

$$\frac{\mu_0}{4 \pi}(\sqrt{2}) \frac{M}{d^3}$$

$$\frac{\mu_0}{4 \pi}(\sqrt{5}) \frac{M}{d^3}$$

$$\left(\frac{2 \mu_0}{\pi}\right) \frac{M}{d^3}$$

MHT CET 2020 16th October Morning Shift

MCQ (Single Correct Answer)

-0

An iron rod is placed parallel to magnetic field of intensity $$2000 \mathrm{~A} / \mathrm{m}$$. The magnetic flux through the rod is $$6 \times 10^{-4} \mathrm{~Wb}$$ and its cross-sectional area is $$3 \mathrm{~cm}^2$$. The magnetic permeability of the rod in $$\frac{\mathrm{Wb}}{\mathrm{A}-\mathrm{m}}$$ is

$$10^{-1}$$

$$10^{-2}$$

$$10^{-4}$$

$$10^{-3}$$

MHT CET 2019 3rd May Morning Shift

MCQ (Single Correct Answer)

-0

A magnetizing field of $5000 \mathrm{~A} / \mathrm{m}$ produces a magnetic flux of $4 \times 10^{-5} \mathrm{~Wb}$ in an iron rod of cross-sectional area $0.4 \mathrm{~cm}^2$. The permeabilit of the rod in Wb/A-m, is

$4 \times 10^{-6}$

$1 \times 10^{-3}$

$2 \times 10^{-4}$

$3 \times 10^{-5}$

MHT CET 2019 2nd May Evening Shift

MCQ (Single Correct Answer)

-0

The magnetization of bar magnet of length 5 cm , cross sectional area $2 \mathrm{~cm}^2$ and net magnetic moment $1 \mathrm{Am}^2$ is

$3 \times 10^5 \mathrm{~A} / \mathrm{m}$

$4 \times 10^5 \mathrm{~A} / \mathrm{m}$

$2 \times 10^5 \mathrm{~A} / \mathrm{m}$

$1 \times 10^5 \mathrm{~A} / \mathrm{m}$

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