MHT CET 2024 10th May Morning Shift | Magnetism and Matter Question 14 | Physics

The correct relation between total magnetic field $(B)$, magnetic intensity $(\mathrm{H})$, permeability of free space $\left(\mu_0\right)$ and susceptibility $(\chi)$ is

$\frac{B}{H}=\mu_0(1-\chi)$

$\frac{\mathrm{B}}{\mathrm{H}}=\mu_0(1+\chi)^2$

$\frac{\mathrm{B}}{\mathrm{H}}=\mu_0(1+\chi)$

$\frac{\mathrm{B}}{\mathrm{H}}=\mu_0(1-\chi)^2$

MHT CET 2024 4th May Evening Shift

MCQ (Single Correct Answer)

-0

A magnetic intensity of $500 \mathrm{~A} / \mathrm{m}$, produces a magnetic flux of $2.4 \times 10^{-5} \mathrm{~Wb}$ in an iron bar of cross-sectional area $0.4 \mathrm{~cm}^2$. The magnetic permeability of the iron bar is

$2.4 \times 10^{-3} \mathrm{~N} / \mathrm{m}^2$

$1.2 \times 10^{-3} \mathrm{~N} / \mathrm{m}^2$

$2.4 \times 10^{-4} \mathrm{~N} / \mathrm{m}^2$

$\quad 1.2 \times 10^{-4} \mathrm{~N} / \mathrm{m}^2$

MHT CET 2024 4th May Morning Shift

MCQ (Single Correct Answer)

-0

The magnetic moments associated with two closely wound circular coils A and B of radius $r_A=10 \mathrm{~cm}$ and $r_B=20 \mathrm{~cm}$ respectively are equal if $\left(N_A, I_A\right.$ and $N_B, I_B$ are number of turns and current of A and B respectively)

$2 N_A \mathrm{I}_{\mathrm{A}}=\mathrm{N}_{\mathrm{B}} \mathrm{I}_{\mathrm{B}}$

$\mathrm{N}_{\mathrm{A}}=2 \mathrm{~N}_{\mathrm{B}}$

$\mathrm{N}_{\mathrm{A}} \mathrm{I}_{\mathrm{A}}=4 \mathrm{~N}_{\mathrm{B}} \mathrm{I}_{\mathrm{B}}$

$ 4 N_A I_A=N_B I_B$

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