MHT CET 2024 11th May Morning Shift | Magnetism and Matter Question 10 | Physics

A bar magnet has length 4 cm , cross-sectional area $2 \mathrm{~cm}^2$ and magnetic moment $6 \mathrm{Am}^2$. The intensity of magnetisation of bar magnet is

$9 \times 10^5 \mathrm{~A} / \mathrm{m}$

$7.5 \times 10^5 \mathrm{~A} / \mathrm{m}$

$4.5 \times 10^5 \mathrm{~A} / \mathrm{m}$

$3.0 \times 10^5 \mathrm{~A} / \mathrm{m}$

MHT CET 2024 10th May Morning Shift

MCQ (Single Correct Answer)

-0

In the following graph of flux density versus magnetizing force, coercivity and retentivity are respectively represented by the points

MHT CET 2024 10th May Morning Shift Physics - Magnetism and Matter Question 11 English

c, b

a, o

d, c

f, e

MHT CET 2024 9th May Evening Shift

MCQ (Single Correct Answer)

-0

The correct relation between total magnetic field $(B)$, magnetic intensity $(\mathrm{H})$, permeability of free space $\left(\mu_0\right)$ and susceptibility $(\chi)$ is

$\frac{B}{H}=\mu_0(1-\chi)$

$\frac{\mathrm{B}}{\mathrm{H}}=\mu_0(1+\chi)^2$

$\frac{\mathrm{B}}{\mathrm{H}}=\mu_0(1+\chi)$

$\frac{\mathrm{B}}{\mathrm{H}}=\mu_0(1-\chi)^2$

MHT CET 2024 4th May Evening Shift

MCQ (Single Correct Answer)

-0

A magnetic intensity of $500 \mathrm{~A} / \mathrm{m}$, produces a magnetic flux of $2.4 \times 10^{-5} \mathrm{~Wb}$ in an iron bar of cross-sectional area $0.4 \mathrm{~cm}^2$. The magnetic permeability of the iron bar is

$2.4 \times 10^{-3} \mathrm{~N} / \mathrm{m}^2$

$1.2 \times 10^{-3} \mathrm{~N} / \mathrm{m}^2$

$2.4 \times 10^{-4} \mathrm{~N} / \mathrm{m}^2$

$\quad 1.2 \times 10^{-4} \mathrm{~N} / \mathrm{m}^2$

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