1
MHT CET 2023 10th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Two dielectric slabs having dielectric constant '$$\mathrm{K}_1$$' and '$$\mathrm{K}_2$$' of thickness $$\frac{\mathrm{d}}{4}$$ and $$\frac{3 \mathrm{~d}}{4}$$ are inserted between the plates as shown in figure. The net capacitance between $$A$$ and $$B$$ is $$\left[\varepsilon_0\right.$$ is permittivity of free space]

MHT CET 2023 10th May Evening Shift Physics - Capacitor Question 53 English

A
$$\frac{2 \mathrm{~A} \varepsilon_0}{\mathrm{~d}}\left[\frac{\mathrm{K}_1 \mathrm{~K}_2}{3 \mathrm{~K}_1+\mathrm{K}_2}\right]$$
B
$$\frac{3 \mathrm{~A} \varepsilon_0}{\mathrm{~d}}\left[\frac{\mathrm{K}_1+\mathrm{K}_2}{\mathrm{~K}_1 \mathrm{~K}_2}\right]$$
C
$$\frac{3 \mathrm{~A}_0}{2 \mathrm{~d}}\left[\frac{\mathrm{K}_1+\mathrm{K}_2}{\mathrm{~K}_1 \mathrm{~K}_2}\right]$$
D
$$\frac{4 A \varepsilon_0}{d}\left[\frac{K_1 K_2}{3 K_1+K_2}\right]$$
2
MHT CET 2023 10th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A parallel plate capacitor has plate area '$$\mathrm{A}$$' and separation between plates is '$$d$$'. It is charged to a potential difference of $$\mathrm{V}_0$$ volt. The charging battery is then disconnected and plates are pulled apart three times the initial distance. The work done to increase the distance between the plates is $$\left(\varepsilon_0=\right.$$ permittivity of free space)

A
$$\frac{3 \varepsilon_0 \mathrm{AV}_0{ }^2}{\mathrm{~d}}$$
B
$$\frac{\varepsilon_0 \mathrm{AV}_0^2}{2 \mathrm{~d}}$$
C
$$\frac{\varepsilon_0 \mathrm{AV}_0{ }^2}{3 \mathrm{~d}}$$
D
$$\frac{\varepsilon_0 \mathrm{AV}_0{ }^2}{\mathrm{~d}}$$
3
MHT CET 2023 10th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Two capacitors $$\mathrm{C}_1=3 \mu \mathrm{F}$$ and $$\mathrm{C}_2=2 \mu \mathrm{F}$$ are connected in series across d.c. source of $$100 \mathrm{~V}$$. The ratio of the potential across $$C_2$$ to $$C_1$$ is

A
$$2: 3$$
B
$$3: 2$$
C
$$6: 5$$
D
$$5: 6$$
4
MHT CET 2023 10th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The mean electrical energy density between plates of a charged air capacitor is (where $$\mathrm{q}=$$ charge on capacitor, $$\mathrm{A}=$$ Area of capacitor plate)

A
$$\frac{q^2}{2 \varepsilon_0 A^2}$$
B
$$\frac{\mathrm{q}}{2 \varepsilon_0 \mathrm{~A}^2}$$
C
$$\frac{\mathrm{q}^2}{2 \varepsilon_0 \mathrm{~A}}$$
D
$$\frac{\varepsilon_0 \mathrm{~A}}{\mathrm{q}^2}$$
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