1
MHT CET 2023 10th May Morning Shift
+1
-0

The mean electrical energy density between plates of a charged air capacitor is (where $$\mathrm{q}=$$ charge on capacitor, $$\mathrm{A}=$$ Area of capacitor plate)

A
$$\frac{q^2}{2 \varepsilon_0 A^2}$$
B
$$\frac{\mathrm{q}}{2 \varepsilon_0 \mathrm{~A}^2}$$
C
$$\frac{\mathrm{q}^2}{2 \varepsilon_0 \mathrm{~A}}$$
D
$$\frac{\varepsilon_0 \mathrm{~A}}{\mathrm{q}^2}$$
2
MHT CET 2023 9th May Evening Shift
+1
-0

A parallel combination of two capacitors of capacities '$$2 ~\mathrm{C}$$' and '$$\mathrm{C}$$' is connected across $$5 \mathrm{~V}$$ battery. When they are fully charged, the charges and energies stored in them be '$$\mathrm{Q}_1$$', '$$Q_2$$' and '$$E_1$$', '$$E_2$$' respectively. Then $$\frac{E_1-E_2}{Q_1-Q_2}$$ in $$\mathrm{J} / \mathrm{C}$$ is (capacity is in Farad, charge in Coulomb and energy in J)

A
$$\frac{5}{4}$$
B
$$\frac{4}{5}$$
C
$$\frac{5}{2}$$
D
$$\frac{2}{5}$$
3
MHT CET 2023 9th May Morning Shift
+1
-0

The capacitance of a parallel plate capacitor is $$2.5 ~\mu \mathrm{F}$$. When it is half filled with a dielectric as shown in figure, its capacitance becomes $$5 ~\mu \mathrm{F}$$. The dielectric constant of the dielectric is

A
7.5
B
3
C
4
D
5
4
MHT CET 2023 9th May Morning Shift
+1
-0

The ratio of potential difference that must be applied across parallel and series combination of two capacitors $$C_1$$ and $$C_2$$ with their capacitance in the ratio $$1: 2$$ so that energy stored in these two cases becomes same is

A
$$3: \sqrt{2}$$
B
$$\sqrt{2}: 3$$
C
$$2: 9$$
D
$$9: 2$$
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