MHT CET 2023 9th May Morning Shift | Electromagnetic Induction Question 69 | Physics

The magnetic flux through a loop of resistance $$10 ~\Omega$$ varying according to the relation $$\phi=6 \mathrm{t}^2+7 \mathrm{t}+1$$, where $$\phi$$ is in milliweber, time is in second at time $$\mathrm{t}=1 \mathrm{~s}$$ the induced e.m.f. is

$$12 \mathrm{~mV}$$

$$7 \mathrm{~mV}$$

$$19 \mathrm{~mV}$$

$$19 \mathrm{~V}$$

MHT CET 2023 9th May Morning Shift

MCQ (Single Correct Answer)

-0

An electron (mass $$\mathrm{m}$$ ) is accelerated through a potential difference of '$$V$$' and then it enters in a magnetic field of induction '$$B$$' normal to the lines. The radius of the circular path is ($$\mathrm{e}=$$ electronic charge)

$$\sqrt{\frac{2 \mathrm{eV}}{\mathrm{m}}}$$

$$\sqrt{\frac{2 \mathrm{Vm}}{\mathrm{eB}^2}}$$

$$\sqrt{\frac{2 V m}{e B}}$$

$$\sqrt{\frac{2 V m}{\mathrm{e}^2 \mathrm{~B}}}$$

MHT CET 2023 9th May Morning Shift

MCQ (Single Correct Answer)

-0

A conducting wire of length $$2500 \mathrm{~m}$$ is kept in east-west direction, at a height of $$10 \mathrm{~m}$$ from the ground. If it falls freely on the ground then the current induced in the wire is (Resistance of wire $$=25 \sqrt{2} \Omega$$, acceleration due to gravity $$\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2, \mathrm{~B}_{\mathrm{H}}=2 \times 10^{-5} \mathrm{~T}$$ )

$$0.2 \mathrm{~A}$$

$$0.02 \mathrm{~A}$$

$$0.01 \mathrm{~A}$$

$$2 \mathrm{~A}$$

MHT CET 2023 9th May Morning Shift

MCQ (Single Correct Answer)

-0

Self inductance of solenoid is

directly proportional to current flowing through the coil.

directly proportional to the length.

directly proportional to its area of cross-section.

inversely proportional to the area of cross-section.

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