1
MHT CET 2025 21st April Morning Shift
MCQ (Single Correct Answer)
+1
-0

Two coils $P$ and $Q$ are kept near each other. When no current flows through coil $P$ and current increases in coil Q at the rate of $10 \mathrm{~A} / \mathrm{S}$, the e.m.f. in coil P is 15 mV . When coil Q carries no current and current of 1.8 A flows through coil $P$, the magnetic flux linked with coil Q is

A
1.8 mWb
B
2.7 mWb
C
1.5 mWb
D
1 mWb
2
MHT CET 2025 21st April Morning Shift
MCQ (Single Correct Answer)
+1
-0

To manufacture a solenoid of length ' $l$ ' and inductance ' $L$ ', the length of the thin wire required is (Diameter of the solenoid is very less than length, $\mu_0=$ permeability of free space)

A
$\left[\frac{4 \pi l L}{\mu_0}\right]^{\frac{1}{2}}$
B
$\left[\frac{2 \pi l}{\mu_0 \mathrm{~L}}\right]^{\frac{1}{2}}$
C
$\left[\frac{4 \pi \mu_0}{l \mathrm{~L}}\right]^{\frac{1}{2}}$
D
$\left[\frac{2 \pi \mu_0 \mathrm{~L}}{l}\right]^{\frac{1}{2}}$
3
MHT CET 2025 21st April Morning Shift
MCQ (Single Correct Answer)
+1
-0

Initially a rectangular coil with length vertical is moving out with constant velocity ' $v$ ' in a constant magnetic field ' $B$ ' towards right. Now the same coil is rotated through $90^{\circ}$ in same plane in same magnetic field B and the coil is moving with same velocity $\mathbf{v}$. The magnitude of induced e.m.f. is now

A
greater than initial induced e.m.f.
B
less than initial induced e.m.f.
C
equal to initial induced e.m.f.
D
sometimes greater and sometimes less than initial induced e.m.f.
4
MHT CET 2025 20th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

A simple pendulum with bob of mass m and conducting wire of length $L$ swings under gravity through an angle $\theta$. The component of earth's magnetic field in the direction perpendicular to swing is B . Maximum e.m.f. induced across the pendulum is ( $\mathrm{g}=$ acceleration due to gravity)

A
$2 \mathrm{BL}(\sqrt{\mathrm{gL}})\left(\sin \frac{\theta}{2}\right)$
B
$\mathrm{BL}(\sqrt{\mathrm{gL}})\left(\sin \frac{\theta}{2}\right)$
C
$\mathrm{BL}(\sqrt{\mathrm{gL}})^2\left(\sin \frac{\theta}{2}\right)$
D
$2 \mathrm{BL}(\sqrt{\mathrm{gL}})\left(\sin ^2 \frac{\theta}{2}\right)$
MHT CET Subjects
EXAM MAP