MHT CET 2025 25th April Morning Shift | Ray Optics Question 3 | Physics

The image of an object approaching a convex mirror of radius of curvature 20 m along its optical axis is observed to move from $\frac{25}{3} \mathrm{~m}$ to $\frac{50}{7} \mathrm{~m}$ in 30 second. The speed of the object in $\mathrm{km} / \mathrm{hr}$ is

2.5

MHT CET 2025 23rd April Evening Shift

MCQ (Single Correct Answer)

-0

A convex lens of refractive index 1.5 has power 3D. It is placed in a liquid of refractive index 2. The new power of the lens is

3 D

0.75 D

1.5 D

2 D

MHT CET 2025 23rd April Evening Shift

MCQ (Single Correct Answer)

-0

Select the correct statement.

If the Brewster's angle for the light propagation from air to glass is ' $\theta$ ', then Brewster's angle for the light propagating from glass to air is $\left(\frac{\pi}{2}-\theta\right)$.

The Brewster's angle for the light propagating from the glass to air is $\tan ^{-1}(\mu)$ where $\mu$ is the refractive index of glass.

The Brewster's angle for light propagating from air to glass is ' $\theta$ ' then Brewster's angle for the light propagating from glass to air is $(\pi+\theta)$.

The Brewster's angle for light propagating from glass to air is $\tan (\mu)$ where is $\mu$ the refractive index of glass.

MHT CET 2025 23rd April Morning Shift

MCQ (Single Correct Answer)

-0

A ray of light is incident on first face of an equilateral glass prism at an angle of incidence ' $I$ '. The emergent ray just grazes along the adjacent face. The refractive index of the the prism is $\sqrt{2}$. The value of angle of incidence at first face is $\left(\sin 45^{\circ}=\frac{1}{\sqrt{2}}, \sin 90^{\circ}=1\right)$

$\quad \sin ^{-1}\left(\sqrt{2} \sin 15^{\circ}\right)$

$\sin ^{-1}\left(\frac{\sin 30^{\circ}}{\sqrt{2}}\right)$

$\quad \cos ^{-1}\left(\sqrt{2} \sin 20^{\circ}\right)$

$\tan ^{-1} \sqrt{2 \sin 15^{\circ}}$

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