MHT CET 2025 23rd April Evening Shift | Ray Optics Question 1 | Physics

If the Brewster's angle for the light propagation from air to glass is ' $\theta$ ', then Brewster's angle for the light propagating from glass to air is $\left(\frac{\pi}{2}-\theta\right)$.

The Brewster's angle for the light propagating from the glass to air is $\tan ^{-1}(\mu)$ where $\mu$ is the refractive index of glass.

The Brewster's angle for light propagating from air to glass is ' $\theta$ ' then Brewster's angle for the light propagating from glass to air is $(\pi+\theta)$.

The Brewster's angle for light propagating from glass to air is $\tan (\mu)$ where is $\mu$ the refractive index of glass.

MHT CET 2025 23rd April Morning Shift

MCQ (Single Correct Answer)

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A ray of light is incident on first face of an equilateral glass prism at an angle of incidence ' $I$ '. The emergent ray just grazes along the adjacent face. The refractive index of the the prism is $\sqrt{2}$. The value of angle of incidence at first face is $\left(\sin 45^{\circ}=\frac{1}{\sqrt{2}}, \sin 90^{\circ}=1\right)$

$\quad \sin ^{-1}\left(\sqrt{2} \sin 15^{\circ}\right)$

$\sin ^{-1}\left(\frac{\sin 30^{\circ}}{\sqrt{2}}\right)$

$\quad \cos ^{-1}\left(\sqrt{2} \sin 20^{\circ}\right)$

$\tan ^{-1} \sqrt{2 \sin 15^{\circ}}$

MHT CET 2025 23rd April Morning Shift

MCQ (Single Correct Answer)

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Let the speed of light and the polarising angle for a given medium be ' $V$ ' and ' $i_p$ ' respectively. The relation between them is : ( $\mathrm{C}=$ speed of light in vacuum)

$\mathrm{V}=\mathrm{C} \cos \left(\mathrm{i}_{\mathrm{p}}\right)$

$V \cos \left(i_p\right)=C \sin \left(i_p\right)$

$\mathrm{C}=\mathrm{V} \cot \left(\mathrm{i}_{\mathrm{p}}\right)$

$\mathrm{V} \sin \left(\mathrm{i}_{\mathrm{p}}\right)=\mathrm{C} \cos \left(\mathrm{i}_{\mathrm{p}}\right)$

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