MHT CET 2025 23rd April Morning Shift | Ray Optics Question 3 | Physics

A ray of light is incident on first face of an equilateral glass prism at an angle of incidence ' $I$ '. The emergent ray just grazes along the adjacent face. The refractive index of the the prism is $\sqrt{2}$. The value of angle of incidence at first face is $\left(\sin 45^{\circ}=\frac{1}{\sqrt{2}}, \sin 90^{\circ}=1\right)$

$\quad \sin ^{-1}\left(\sqrt{2} \sin 15^{\circ}\right)$

$\sin ^{-1}\left(\frac{\sin 30^{\circ}}{\sqrt{2}}\right)$

$\quad \cos ^{-1}\left(\sqrt{2} \sin 20^{\circ}\right)$

$\tan ^{-1} \sqrt{2 \sin 15^{\circ}}$

MHT CET 2025 23rd April Morning Shift

MCQ (Single Correct Answer)

-0

Let the speed of light and the polarising angle for a given medium be ' $V$ ' and ' $i_p$ ' respectively. The relation between them is : ( $\mathrm{C}=$ speed of light in vacuum)

$\mathrm{V}=\mathrm{C} \cos \left(\mathrm{i}_{\mathrm{p}}\right)$

$V \cos \left(i_p\right)=C \sin \left(i_p\right)$

$\mathrm{C}=\mathrm{V} \cot \left(\mathrm{i}_{\mathrm{p}}\right)$

$\mathrm{V} \sin \left(\mathrm{i}_{\mathrm{p}}\right)=\mathrm{C} \cos \left(\mathrm{i}_{\mathrm{p}}\right)$

MHT CET 2025 22nd April Evening Shift

MCQ (Single Correct Answer)

-0

A concave lens (refractive index $=1.5$ ) has both surfaces of same radius of curvature R . If it is immersed in a liquid of refractive index 1.75 it will act as a

concave lens of focal length (3.5) R

concave lens of focal length 2 R .

convex lens of focal length (3.5) R

convex lens of focal length $2 R$

MHT CET 2025 22nd April Morning Shift

MCQ (Single Correct Answer)

-0

Two thin lenses having $\mathrm{R}_1, \mathrm{R}_2$ as the radii of curved surfaces are kept coaxially together. Their power is proportional to

$\mathrm{R}_1+\mathrm{R}_2$

$\mathrm{R}_1-\mathrm{R}_2$

$\frac{\mathrm{R}_1 \mathrm{R}_2}{\mathrm{R}_1+\mathrm{R}_2}$

$\frac{R_1+R_2}{R_1 R_2}$

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