1
MHT CET 2025 19th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

A stone is projected with kinetic energy E, making an angle $\theta$ with the horizontal. When it reaches a highest point, its kinetic energy is

A
$\mathrm{E}^2 \sin ^2 \theta$
B
$\mathrm{E} \sin \theta$
C
$E \cos ^2 \theta$
D
$\mathrm{E} \cos \theta$
2
MHT CET 2025 19th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
A stone of mass 1 kg tied to a light inextensible string of length $L=\frac{5}{3} m$ is rotating in a circular path of radius $L$ in a vertical plane. If the ratio of maximum tension in the string to the minimum tension in the string is 3 , the speed of the stone at the highest point of the circle is ( $\mathrm{g}=$ acceleration due to gravity)
A
$\sqrt{\mathrm{gL}}$
B
$\sqrt{2 \mathrm{gL}}$
C
$\sqrt{4 \mathrm{gL}}$
D
$\sqrt{8 \mathrm{gL}}$
3
MHT CET 2024 16th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The power $(\mathrm{P})$ is supplied to a rotating body having moment of inertia ' I ' and angular acceleration ' $\alpha$ '. Its instantaneous angular velocity ' $\omega$ ' is

A
$\mathrm{P}(\mathrm{I} \alpha)^{-1}$
B
$\mathrm{P}^{-1}(\mathrm{I} \alpha)^{-1}$
C
$P \alpha^{-1} \mathrm{I}$
D
$\mathrm{PIa}$
4
MHT CET 2024 16th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A simple pendulum of length L has mass m and it oscillates freely with amplitude A. At extreme position, its potential energy is ( $\mathrm{g}=$ acceleration due to gravity)

A
$\frac{\mathrm{mgA}}{2 \mathrm{~L}}$
B
$\frac{\mathrm{mgA}^2}{\mathrm{~L}}$
C
$\frac{\mathrm{mgA}}{\mathrm{L}}$
D
$\frac{\mathrm{mgA}^2}{2 \mathrm{~L}}$
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