Using variation of force and time given below, final velocity of a particle of mass $$2 \mathrm{~kg}$$ moving with initial velocity $$6 \mathrm{~m} / \mathrm{s}$$ will be

A ball of mass '$$\mathrm{m}$$' is dropped from a height '$$\mathrm{s}$$' on a horizontal platform fixed at the top of a vertical spring. The platform is depressed by a distance '$$h$$'. The spring constant is ( $$\mathrm{g}=$$ acceleration due to gravity)

If a lighter body of mass '$$\mathrm{M}_1$$' and velocity '$$\mathrm{V}_1$$' and a heavy body (mass $$M_2$$ and velocity $$V_2$$ ) have the same kinetic energy then

A stone is projected vertically upwards with speed '$$v$$'. Another stone of same mass is projected at an angle of $$60^{\circ}$$ with the vertical with the same speed '$$v$$'. The ratio of their potential energies at the highest points of their journey is $$\left[\sin 30^{\circ}=\cos 60^{\circ}=0.5, \cos 30^{\circ}=\sin 60^{\circ}=\frac{\sqrt{3}}{2}\right]$$