1
MHT CET 2020 19th October Evening Shift
MCQ (Single Correct Answer)
+1
-0

A domain in a ferromagnetic substance is in the form of a cube of side $1 \mu \mathrm{~m}$. If it contains $8 \times 10^{10}$ atoms and each atomic dipole has a dipole moment of $9 \times 10^{-24} \mathrm{Am}^2$, then the magnetisation of the domain is

A
$7.2 \times 10^5 \mathrm{Am}^{-1}$
B
$7.2 \times 10^3 \mathrm{Am}^{-1}$
C
$7.2 \times 10^9 \mathrm{Am}^{-1}$
D
$7.2 \times 10^{12} \mathrm{Am}^{-1}$
2
MHT CET 2020 19th October Evening Shift
MCQ (Single Correct Answer)
+1
-0

For a paramagnetic substance, the magnetic susceptibility is

A
large and negative
B
small and positive
C
large and positive
D
small and negative
3
MHT CET 2020 16th October Evening Shift
MCQ (Single Correct Answer)
+1
-0

The magnetic susceptibility of a paramagnetic material at $$-73^{\circ} \mathrm{C}$$ is 0.0075. Its value at $$-173^{\circ} \mathrm{C}$$ will be

A
0.0150
B
0.0075
C
0.0030
D
0.0045
4
MHT CET 2020 16th October Evening Shift
MCQ (Single Correct Answer)
+1
-0

If the angle of dip at places $$A$$ and $$B$$ are $$30^{\circ}$$ and $$45^{\circ}$$ respectively, then the ratio of horizontal component of earth's magnetic field at $$A$$ to that at $$B$$ will be $$\left[\sin 45^{\circ}=\cos 45^{\circ}=\frac{1}{\sqrt{2}}, \sin \frac{\pi}{6}=\frac{1}{2}, \cos \frac{\pi}{6}=\frac{\sqrt{3}}{2}\right]$$

A
$$\sqrt{2}: 1$$
B
$$1: \sqrt{2}$$
C
$$\sqrt{3}: \sqrt{2}$$
D
$$\sqrt{2}: \sqrt{3}$$
MHT CET Subjects
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