GATE EE 2012 | Continuous Time Signal Laplace Transform Question 4 | Signals and Systems

GATE EE 2012

MCQ (Single Correct Answer)

-0.3

The unilateral Laplace transform of f(t) is $$\frac1{s^2\;+\;s\;+\;1}$$. The unilateral Laplace transform of tf(t) is

$$-\frac s{\displaystyle\left(s^2\;+\;s\;+\;1\right)^2}$$

$$-\frac{2s+1}{\displaystyle\left(s^2\;+\;s\;+\;1\right)^2}$$

$$\frac s{\displaystyle\left(s^2\;+\;s\;+\;1\right)^2}$$

$$\frac{2s+1}{\displaystyle\left(s^2\;+\;s\;+\;1\right)^2}$$

GATE EE 2002

MCQ (Single Correct Answer)

-0.3

Let Y(s) be the Laplace transformation of the function y(t), then the final value of the function is

$$\underset{s\rightarrow0}{L\mathrm{im}\;}Y\left(s\right)$$

$$\underset{s\rightarrow\infty}{L\mathrm{im}\;}Y\left(s\right)$$

$$\underset{s\rightarrow0}{L\mathrm{im}\;}sY\left(s\right)$$

$$\underset{s\rightarrow\infty}{L\mathrm{im}\;}sY\left(s\right)$$

GATE EE 1995

MCQ (Single Correct Answer)

-0.3

The Laplace transformation of f(t) is F(s). Given F(s)=$$\frac\omega{s^2+\omega^2}$$, the final value of f(t) is

infinity

zero

one

none of these

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