1
GATE EE 2013
MCQ (Single Correct Answer)
+2
-0.6
The equation $$\left[ {\matrix{ 2 & { - 2} \cr 1 & { - 1} \cr } } \right]\left[ {\matrix{ {{x_1}} \cr {{x_2}} \cr } } \right] = \left[ {\matrix{ 0 \cr 0 \cr } } \right]$$ has
A
no solution
B
only one solution
C
non-zero unique solution
D
multiple solutions
2
GATE EE 2013
MCQ (Single Correct Answer)
+2
-0.6
A matrix has eigen values $$-1$$ and $$-2.$$ The corresponding eigenvectors are $$\left[ {\matrix{ 1 \cr { - 1} \cr } } \right]$$ and $$\left[ {\matrix{ 1 \cr { - 2} \cr } } \right]$$ respectively. The matrix is
A
$$\left[ {\matrix{ 1 & 1 \cr { - 1} & { - 2} \cr } } \right]$$
B
$$\left[ {\matrix{ 1 & 2 \cr { - 2} & { - 4} \cr } } \right]$$
C
$$\left[ {\matrix{ { - 1} & 0 \cr 0 & { - 2} \cr } } \right]$$
D
$$\left[ {\matrix{ 0 & 1 \cr { - 2} & { - 3} \cr } } \right]$$
3
GATE EE 2011
MCQ (Single Correct Answer)
+2
-0.6
The two vectors $$\left[ {\matrix{ 1 & 1 & 1 \cr } } \right]$$ and $$\left[ {\matrix{ 1 & a & {{a^2}} \cr } } \right]$$ where $$a = - {1 \over 2} + j{{\sqrt 3 } \over 2}$$ and $$j = \sqrt { - 1} $$ are
A
orthonormal
B
orthogonal
C
parallel
D
collinear
4
GATE EE 2011
MCQ (Single Correct Answer)
+2
-0.6
The matrix $$\left[ A \right] = \left[ {\matrix{ 2 & 1 \cr 4 & { - 1} \cr } } \right]$$ is decomposed into a product of lower triangular matrix $$\left[ L \right]$$ and an upper triangular $$\left[ U \right].$$ The properly decomposed $$\left[ L \right]$$ and $$\left[ U \right]$$ matrices respectively are
A
$$\left[ {\matrix{ 1 & 0 \cr 4 & { - 1} \cr } } \right]$$ and $$\left[ {\matrix{ 1 & 1 \cr 0 & { - 2} \cr } } \right]$$
B
$$\left[ {\matrix{ 1 & 0 \cr 2 & 1 \cr } } \right]$$ and $$\left[ {\matrix{ 2 & 1 \cr 0 & { - 3} \cr } } \right]$$
C
$$\left[ {\matrix{ 1 & 0 \cr 4 & 1 \cr } } \right]\,$$ and $$\left[ {\matrix{ 2 & 1 \cr 0 & { - 1} \cr } } \right]$$
D
$$\left[ {\matrix{ 2 & 0 \cr 4 & { - 3} \cr } } \right]$$ and $$\left[ {\matrix{ 1 & {0.5} \cr 0 & 1 \cr } } \right]$$
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