1
GATE EE 2011
MCQ (Single Correct Answer)
+1
-0.3
Given two continuous time signals $$x\left(t\right)=e^{-t}$$ and $$y\left(t\right)=e^{-2t}$$ which exist for t > 0, the convolution z(t) = x(t)*y(t) is
A
$$e^{-t}-e^{-2t}$$
B
$$e^{-3t}$$
C
$$e^{+t}$$
D
$$e^{-t}\;+\;e^{-2t}$$
2
GATE EE 2010
MCQ (Single Correct Answer)
+1
-0.3
The system represented by the input-output relationship $$y\left(t\right)=\int_{-\infty}^{5t}x\left(\tau\right)d\tau$$, t > 0 is
A
Linear and causal
B
Linear but not causal
C
Causal but not linear
D
Neither linear nor causal
3
GATE EE 2010
MCQ (Single Correct Answer)
+1
-0.3
For the system $$\frac2{\left(s+1\right)}$$, the approximate time taken for a step response to reach 98% of its final value is
A
1 s
B
2 s
C
4 s
D
8 s
4
GATE EE 2009
MCQ (Single Correct Answer)
+1
-0.3
A linear Time Invariant system with an impulse response $$h(t)$$ produces output $$y(t)$$ when input $$x(t)$$ is applied. When the input $$x\left( {t - \tau } \right)$$ is applied to a system with response $$h\left( {t - \tau } \right)$$, the output will be
A
$$y\left( t \right)$$
B
$$y\left( {2\left( {t - \tau } \right)} \right)$$
C
$$y\left( {t - \tau } \right)$$
D
$$y\left( {t - 2\tau } \right)$$
GATE EE Subjects
EXAM MAP