1
GATE EE 2010
MCQ (Single Correct Answer)
+1
-0.3
For the system $$\frac2{\left(s+1\right)}$$, the approximate time taken for a step response to reach 98% of its final value is
A
1 s
B
2 s
C
4 s
D
8 s
2
GATE EE 2010
MCQ (Single Correct Answer)
+1
-0.3
The system represented by the input-output relationship $$y\left(t\right)=\int_{-\infty}^{5t}x\left(\tau\right)d\tau$$, t > 0 is
A
Linear and causal
B
Linear but not causal
C
Causal but not linear
D
Neither linear nor causal
3
GATE EE 2009
MCQ (Single Correct Answer)
+1
-0.3
A linear Time Invariant system with an impulse response $$h(t)$$ produces output $$y(t)$$ when input $$x(t)$$ is applied. When the input $$x\left( {t - \tau } \right)$$ is applied to a system with response $$h\left( {t - \tau } \right)$$, the output will be
A
$$y\left( t \right)$$
B
$$y\left( {2\left( {t - \tau } \right)} \right)$$
C
$$y\left( {t - \tau } \right)$$
D
$$y\left( {t - 2\tau } \right)$$
4
GATE EE 2008
MCQ (Single Correct Answer)
+1
-0.3
A signal $${e^{ - \alpha t}}\,\sin \left( {\omega t} \right)$$ is the input to a real Linear Time Invariant system. Given $$K$$ and $$\phi $$ are constants, the output of the system will be of the form $$K{e^{ - \beta t}}\,\sin \,\left( {\upsilon t + \phi } \right)$$ where
A
$$\beta $$ need not be equal to $$\alpha $$ but $$\upsilon $$ equal to
B
$$\upsilon $$ need not be equal to $$\omega $$ but $$\beta $$ equal to $$\alpha $$
C
$$\beta $$ equal to $$\alpha $$ and $$\upsilon $$ equal to $$\omega $$
D
$$\beta $$ need not be equal to $$\alpha $$ and $$\upsilon $$ need not be equal to $$\omega $$
GATE EE Subjects
EXAM MAP
Medical
NEET
Graduate Aptitude Test in Engineering
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CBSE
Class 12