MHT CET 2025 21st April Morning Shift | Electromagnetic Induction Question 11 | Physics

To manufacture a solenoid of length ' $l$ ' and inductance ' $L$ ', the length of the thin wire required is (Diameter of the solenoid is very less than length, $\mu_0=$ permeability of free space)

$\left[\frac{4 \pi l L}{\mu_0}\right]^{\frac{1}{2}}$

$\left[\frac{2 \pi l}{\mu_0 \mathrm{~L}}\right]^{\frac{1}{2}}$

$\left[\frac{4 \pi \mu_0}{l \mathrm{~L}}\right]^{\frac{1}{2}}$

$\left[\frac{2 \pi \mu_0 \mathrm{~L}}{l}\right]^{\frac{1}{2}}$

MHT CET 2025 21st April Morning Shift

MCQ (Single Correct Answer)

-0

Initially a rectangular coil with length vertical is moving out with constant velocity ' $v$ ' in a constant magnetic field ' $B$ ' towards right. Now the same coil is rotated through $90^{\circ}$ in same plane in same magnetic field B and the coil is moving with same velocity $\mathbf{v}$. The magnitude of induced e.m.f. is now

greater than initial induced e.m.f.

less than initial induced e.m.f.

equal to initial induced e.m.f.

sometimes greater and sometimes less than initial induced e.m.f.

MHT CET 2025 20th April Evening Shift

MCQ (Single Correct Answer)

-0

A simple pendulum with bob of mass m and conducting wire of length $L$ swings under gravity through an angle $\theta$. The component of earth's magnetic field in the direction perpendicular to swing is B . Maximum e.m.f. induced across the pendulum is ( $\mathrm{g}=$ acceleration due to gravity)

$2 \mathrm{BL}(\sqrt{\mathrm{gL}})\left(\sin \frac{\theta}{2}\right)$

$\mathrm{BL}(\sqrt{\mathrm{gL}})\left(\sin \frac{\theta}{2}\right)$

$\mathrm{BL}(\sqrt{\mathrm{gL}})^2\left(\sin \frac{\theta}{2}\right)$

$2 \mathrm{BL}(\sqrt{\mathrm{gL}})\left(\sin ^2 \frac{\theta}{2}\right)$

MHT CET 2025 20th April Evening Shift

MCQ (Single Correct Answer)

-0

Three inductances are connected as shown in the figure. The equivalent inductance between A and b is

MHT CET 2025 20th April Evening Shift Physics - Electromagnetic Induction Question 13 English

2.25 H

1.20 H

0.225 H

0.120 H

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