MHT CET 2023 14th May Evening Shift | Electromagnetic Induction Question 41 | Physics

The self induction (L) produced by solenoid of length '$$l$$' having '$$\mathrm{N}$$' number of turns and cross sectional area '$$A$$' is given by the formula ($$\phi=$$ magnetic flux, $$\mu_0=$$ permeability of vacuum)

$$\mathrm{L}=\mathrm{N} \phi$$

$$\mathrm{L}=\mu_0 \mathrm{NAl}$$

$$\mathrm{L}=\frac{\mu_0 \mathrm{~N}^2 \mathrm{~A}}{l}$$

$$\mathrm{L}=\frac{\mu_0 \mathrm{NA}}{l}$$

MHT CET 2023 14th May Morning Shift

MCQ (Single Correct Answer)

-0

A magnetic field of $$2 \times 10^{-2} \mathrm{~T}$$ acts at right angles to a coil of area $$100 \mathrm{~cm}^2$$ with 50 turns. The average e.m.f. induced in the coil is $$0.1 \mathrm{~V}$$, when it is removed from the field in time '$$t$$'. The value of '$$t$$' is

$$2 \times 10^{-3} \mathrm{~s}$$

$$0.5 \mathrm{~s}$$

$$0.1 \mathrm{~s}$$

$$1 \mathrm{~s}$$

MHT CET 2023 14th May Morning Shift

MCQ (Single Correct Answer)

-0

The alternating e.m.f. induced in the secondary coil of a transformer is mainly due to

varying electric field

varying magnetic field

the iron core

heat produced in the coil

MHT CET 2023 13th May Evening Shift

MCQ (Single Correct Answer)

-0

A metal disc of radius $$R$$ rotates with an angular velocity $$\omega$$ about an axis perpendicular to its plane passing through its centre in a magnetic field of induction $$B$$ acting perpendicular to the plane of the disc. The magnitude of induced emf between the rim and axis of the disc is

$$\pi B R^2$$

$$\frac{2 \pi^2 B R^2}{\omega}$$

$$\pi B R^2 \omega$$

$$\frac{B R^2 \omega}{2}$$

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