1
MHT CET 2021 24th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

The ratio of maximum to minimum wavelength in Balmer series of hydrogen atom is

A
36 : 5
B
3 : 4
C
9 : 5
D
5 : 9
2
MHT CET 2021 23rd September Evening Shift
MCQ (Single Correct Answer)
+1
-0

Energy of electron in the second orbit of hydrogen atom is $$\mathrm{E}$$. The energy of electron '$$\mathrm{E}_3$$' in the third orbit of helium $$(\mathrm{He})$$ atom will be

A
$$\mathrm{E}_3=\frac{4 \mathrm{E}}{9}$$
B
$$\mathrm{E}_3=\frac{16 \mathrm{E}}{3}$$
C
$$\mathrm{E}_3=\frac{16 \mathrm{E}}{9}$$
D
$$\mathrm{E}_3=\frac{4 \mathrm{E}}{3}$$
3
MHT CET 2021 23th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

The shortest wavelength for Lyman series is 912 $$\mathop A\limits^o $$. The longest wavelength in Paschen series is

A
1216 $$\mathop A\limits^o $$
B
3646 $$\mathop A\limits^o $$
C
18760 $$\mathop A\limits^o $$
D
8208 $$\mathop A\limits^o $$
4
MHT CET 2021 23th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

In the Bohr model, an electron moves in a circular orbit around the nucleus. Considering an orbiting electron to be a circular current loop, the magnetic moment of the hydrogen atom, when the electron is in nth excited state, is

(e = electronic charge, m$$_e$$ = mass of the electron, h = Planck's constant)

A
$$ \left(\frac{\mathrm{e}}{\mathrm{m}_{\mathrm{e}}}\right) \frac{\mathrm{nh}}{2 \pi} $$
B
$$ \mathrm{\left(\frac{e}{m_e}\right) \frac{n^2 h}{2 \pi}} $$
C
$$ \mathrm{\left(\frac{e}{2 m_e}\right) \frac{n^2 h}{2 \pi}} $$
D
$$ \left(\frac{\mathrm{e}}{2 \mathrm{~m}_{\mathrm{e}}}\right) \frac{\mathrm{nh}}{2 \pi} $$
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