MHT CET 2021 24th September Morning Shift | Atoms and Nuclei Question 32 | Physics

Energy of electron in the second orbit of hydrogen atom is $$\mathrm{E}$$. The energy of electron '$$\mathrm{E}_3$$' in the third orbit of helium $$(\mathrm{He})$$ atom will be

$$\mathrm{E}_3=\frac{4 \mathrm{E}}{9}$$

$$\mathrm{E}_3=\frac{16 \mathrm{E}}{3}$$

$$\mathrm{E}_3=\frac{16 \mathrm{E}}{9}$$

$$\mathrm{E}_3=\frac{4 \mathrm{E}}{3}$$

MHT CET 2021 23th September Morning Shift

MCQ (Single Correct Answer)

-0

The shortest wavelength for Lyman series is 912 $$\mathop A\limits^o $$. The longest wavelength in Paschen series is

1216 $$\mathop A\limits^o $$

3646 $$\mathop A\limits^o $$

18760 $$\mathop A\limits^o $$

8208 $$\mathop A\limits^o $$

MHT CET 2021 23th September Morning Shift

MCQ (Single Correct Answer)

-0

In the Bohr model, an electron moves in a circular orbit around the nucleus. Considering an orbiting electron to be a circular current loop, the magnetic moment of the hydrogen atom, when the electron is in nth excited state, is

(e = electronic charge, m$$_e$$ = mass of the electron, h = Planck's constant)

$$ \left(\frac{\mathrm{e}}{\mathrm{m}_{\mathrm{e}}}\right) \frac{\mathrm{nh}}{2 \pi} $$

$$ \mathrm{\left(\frac{e}{m_e}\right) \frac{n^2 h}{2 \pi}} $$

$$ \mathrm{\left(\frac{e}{2 m_e}\right) \frac{n^2 h}{2 \pi}} $$

$$ \left(\frac{\mathrm{e}}{2 \mathrm{~m}_{\mathrm{e}}}\right) \frac{\mathrm{nh}}{2 \pi} $$

PREVIOUS NEXT

MHT CET Subjects