MHT CET 2025 22nd April Evening Shift | Waves Question 13 | Physics

The lengths of the two organ pipes open at both ends are ' L ' and $\left(\mathrm{L}+\mathrm{L}_1\right)$. If they are sounded together, the beat frequency will be ( $\mathrm{v}=$ velocity of sound in air)

$\frac{2 v L_1}{L\left(L+L_1\right)}$

$\frac{2 \mathrm{~L}\left(\mathrm{~L}+\mathrm{L}_1\right)}{\mathrm{vL}_1}$

$\frac{\mathrm{vL}_1}{\mathrm{~L}\left(\mathrm{~L}+\mathrm{L}_1\right)}$

$\frac{v L_1}{2 L\left(L+L_1\right)}$

MHT CET 2025 22nd April Morning Shift

MCQ (Single Correct Answer)

-0

A person standing between two parallel cliffs fires a gun and hears two echoes, first echo after 1 second and the second echo after 3 second. The distance between the two cliffs is (Velocity of sound $=340 \mathrm{~m} / \mathrm{s}$ )

340 m

680 m

1020 m

1360 m

MHT CET 2025 22nd April Morning Shift

MCQ (Single Correct Answer)

-0

An organ pipe has fundamental frequency 80 Hz . If its one end is closed, the frequencies produced will be (in Hz ) (Neglect end correction)

$40,80,120,160$

$40,80,160,240$

$40,120,200,280$

$80,160,240,320$

MHT CET 2025 22nd April Morning Shift

MCQ (Single Correct Answer)

-0

The equation of wave is $y=60 \sin (1200 t-6 x)$, where ' $y$ ' is in micron, ' $t$ ' is in second and ' $x$ ' is in metre. The ratio of maximum particle velocity to the wave velocity of wave propagation is

$3.6 \times 10^{-5}$

$3.6 \times 10^{-4}$

$3.6 \times 10^{-6}$

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