1
MHT CET 2025 20th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

The length of closed and open pipe is same. The ratio of frequency of $\mathrm{n}^{\text {th }}$ overtone for closed pipe to that of open pipe is (Neglect end correction)

A
$\frac{(2 n+1)}{2(n+1)}$
B
$\frac{(\mathrm{n}+1)}{(2 \mathrm{n}+1)}$
C
$\quad \frac{(2 n-1)}{2(n+1)}$
D
$\frac{(n-1)}{2(n+1)}$
2
MHT CET 2025 20th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

The frequency of a stretched uniform wire of length $L$ under tension is in resonance with the fundamental frequency of a closed pipe of same length. If the tension in the wire is increased by 8 N , it is in resonance with the first overtone of the same closed pipe. The initial tension in the wire is

A
4 N
B
$\quad \frac{1}{2} \mathrm{~N}$
C
2 N
D
1 N
3
MHT CET 2025 20th April Morning Shift
MCQ (Single Correct Answer)
+1
-0

When an observer moves towards a stationary source with velocity ' $\mathrm{V}_1$ ', the apparent frequency of emitted note is ' $\mathrm{F}_1$ '. When observer moves away from stationary source with velocity ' $\mathrm{V}_1$ ' the apparent frequency is ' $\mathrm{F}_2$ '. If ' v ' is velocity of sound in air and $\frac{\mathrm{F}_1}{\mathrm{~F}_2}=2$, then $\frac{\mathrm{V}}{\mathrm{V}_1}$ is equal to

A
6
B
5
C
3
D
4
4
MHT CET 2025 20th April Morning Shift
MCQ (Single Correct Answer)
+1
-0

In fundamental mode, the time required for the sound wave to reach up to closed end of a pipe filled with air is ' $t$ ' second. The frequency of vibration of air column is (Neglect end correction)

A
$(4 t)^{-1}$
B
$(2 t)^{-1}$
C
$4 t$
D
$2 t$
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