1
MHT CET 2021 20th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

The equation of wave is given by $$\mathrm{y}=10 \sin \left(\frac{2 \pi \mathrm{t}}{30}+\alpha\right)$$. If the displacement is $$5 \mathrm{~cm}$$ at $$\mathrm{t}=0$$, then the total phase at $$\mathrm{t}=7.5 \mathrm{~s}$$ will be

$$\left[\sin 30^{\circ}=\cos 60^{\circ}=\frac{1}{2}, \cos 30^{\circ}=\sin 60^{\circ}=\frac{\sqrt{3}}{2}\right] $$

A
$$\frac{\pi}{3} \mathrm{rad}$$
B
$$\frac{\pi}{2} \mathrm{rad}$$
C
$$\frac{2 \pi}{5} \mathrm{rad}$$
D
$$\frac{2 \pi}{3} \mathrm{rad}$$
2
MHT CET 2021 20th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

A sonometer wire resonates with 4 antinodes between two bridges for a given tuning fork, when 1 kg mass is suspended from the wire. Using same fork, when mass M is suspended, the wire resonates producing 2 antinodes between the two bridges (distance between two bridges is as before). The value of M is

A
2.5 kg
B
3.5 kg
C
4 kg
D
1 kg
3
MHT CET 2021 20th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

Two wires of same material of radius 'r' and '2r' respectively are welded together end to end. The combination is then used as a sonometer wire under tension 'T'. The joint is kept midway between the two bridges. The ratio of the number of loops formed in the wires such that the joint is a node is

A
1 : 5
B
1 : 2
C
1 : 4
D
1 : 3
4
MHT CET 2021 20th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

The frequency of a tuning fork is 'n' Hz and velocity of sound in air is 'V' m/s. When the tuning fork completes 'x' vibrations, the distance travelled by the wave is

A
$$\mathrm{\frac{V}{xn}}$$
B
$$\mathrm{\frac{Vn}{x}}$$
C
$$\mathrm{\frac{xV}{n}}$$
D
$$\mathrm{\frac{x}{Vn}}$$
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