1
MHT CET 2025 21st April Morning Shift
MCQ (Single Correct Answer)
+2
-0

The area inside the parabola $y^2=4 \mathrm{a} x$, between the lines $x=\mathrm{a}$ and $x=4 \mathrm{a}$ is equal to

A
$4 a^2$ sq. units
B
$8 \mathrm{a}^2$ sq. units
C
$\frac{56 \mathrm{a}^2}{3}$ sq. units
D
$\frac{35 \mathrm{a}^2}{3}$ sq. units
2
MHT CET 2025 20th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

The area of the region bounded by $\frac{x^2}{9}+\frac{y^2}{4}=1$ and the line $\frac{x}{3}+\frac{y}{2}=1$ is

A
$\frac{1}{2}(\pi-2)$ sq. units
B
$\frac{3}{2}(\pi-2)$ sq. units
C
$\frac{5}{4}(\pi-2)$ sq. units
D
$\frac{2}{3}(\pi-2)$ sq. units
3
MHT CET 2025 19th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

The area enclosed between the curves $y^2=4 x$ and $y=|x|$ is

A
$\frac{8}{3}$ sq. units
B
$\frac{5}{3}$ sq. units
C
$\frac{4}{3}$ sq. units
D
$\frac{2}{3}$ sq. units
4
MHT CET 2025 19th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
The ratio of the areas bounded by the curves $y=\cos x$ and $y=\cos 2 x$ between $x=0, x=\frac{\pi}{3}$ and X -axis is
A
$\sqrt{2}: 1$
B
$1: 1$
C
$2: 1$
D
$1: 3$
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