MHT CET 2021 21th September Morning Shift | Atoms and Nuclei Question 75 | Physics

'$$\lambda_1$$' is the wavelength of series limit of Lyman series, '$$\lambda_2$$' is the wavelength of the first line line of Lyman series and '$$\lambda_3$$' is the series limit of the Balmer series. Then the relation between $$\lambda_1, \lambda_2$$ and $$\lambda_3$$ is

$$\frac{1}{\lambda_1}-\frac{1}{\lambda_2}=\frac{1}{\lambda_3}$$

$$\frac{1}{\lambda_1}=\frac{1}{\lambda_2}-\frac{1}{\lambda_3}$$

$$\lambda_2=\lambda_1+\lambda_3$$

$$\lambda_1=\lambda_2+\lambda_3$$

MHT CET 2021 20th September Evening Shift

MCQ (Single Correct Answer)

-0

A sample of radioactive element contains $$8 \times 10^{16}$$ active nuclei. The halt-life of the element is 15 days. The number of nuclei decayed after 60 days is

$$7.5 \times 10^{16}$$

$$2.0 \times 10^{16}$$

$$0.5 \times 10^{16}$$

$$4.0 \times 10^{16}$$

MHT CET 2021 20th September Evening Shift

MCQ (Single Correct Answer)

-0

The P.E. 'U' of a moving particle of mass 'm' varies with 'x'-axis as shown in figure. The deBroglie wavelength or the particle in the regions $$0 \leq x \leq 1$$ and $$x > 1$$ are $$\lambda_1$$ and $$\lambda_2$$ respectively. II the total energy of the particle is '$$\mathrm{nE}$$', then the ratio $$\lambda_1 / \lambda_2$$ is

MHT CET 2021 20th September Evening Shift Physics - Atoms and Nuclei Question 88 English

$$\sqrt{\frac{n^2}{n-1}}$$

$$\sqrt{\frac{n-1}{n}}$$

$$\sqrt{\frac{\mathrm{n}}{\mathrm{n}-1}}$$

$$\sqrt{\frac{\mathrm{n}(\mathrm{n}-1)}{\mathrm{n}}}$$

MHT CET 2021 20th September Evening Shift

MCQ (Single Correct Answer)

-0

The gyromagnetic ratio of an electron in an hydrogen atom, according to Bohr model is

decreases with the quantum number 'n'.

independent of which orbit it is in.

negative

positive

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