If the line $3 x+4 y-24=0$ intersects X and Y axes in points A and B respectively then incentre of the triangle OAB where O is origin is

The equation $x^2-3 x y+2 y^2+3 x-5 y+2=0$ represents a pair of straight lines. If $\theta$ is the angle between them, then the value of $\cos \theta$ is equal to

The acute angle between the line $4 x-2 y+13=0$ and the line which makes equal intercepts with the co-ordinate axes is

If the pair of lines $3 x^2-5 x y+\mathrm{p} y^2=0$ and $6 x^2-x y-5 y^2=0$ have one line common, then $\mathrm{p}=$