1
MHT CET 2023 13th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

An isotope of the original nucleus can be formed in a radioactive decay, with the emission of following particles.

A
one $$\alpha$$ and one $$\beta$$
B
one $$\alpha$$ and two $$\beta$$
C
one $$\alpha$$ and four $$\beta$$
D
four $$\alpha$$ and one $$\beta$$
2
MHT CET 2023 12th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Two different radioactive elements with half lives '$$\mathrm{T}_1$$' and '$$\mathrm{T}_2$$' have undecayed atoms '$$\mathrm{N}_1$$' and '$$\mathrm{N}_2$$' respectively present at a given instant. The ratio of their activities at that instant is

A
$$\frac{\mathrm{N}_1 \mathrm{~T}_1}{\mathrm{~N}_2 \mathrm{~T}_2}$$
B
$$\frac{\mathrm{N}_2 \mathrm{~T}_2}{\mathrm{~N}_1 \mathrm{~T}_1}$$
C
$$\frac{\mathrm{N}_1 \mathrm{~T}_2}{\mathrm{~N}_2 \mathrm{~T}_1}$$
D
$$\frac{\mathrm{N}_1 \mathrm{~N}_2}{\mathrm{~T}_1 \mathrm{~T}_2}$$
3
MHT CET 2023 12th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

In Balmer series, wavelength of the $$2^{\text {nd }}$$ line is '$$\lambda_1$$' and for Paschen series, wavelength of the $$1^{\text {st }}$$ line is '$$\lambda_2$$', then the ratio '$$\lambda_1$$' to '$$\lambda_2$$' is

A
$$5: 128$$
B
$$5: 81$$
C
$$7: 27$$
D
$$9: 132$$
4
MHT CET 2023 12th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

In Lyman series, series limit of wavelength is $$\lambda_1$$. The wavelength of first line of Lyman series is $$\lambda_2$$ and in Balmer series, the series limit of wavelength is $$\lambda_3$$. Then the relation between $$\lambda_1$$, $$\lambda_2$$ and $$\lambda_3$$ is

A
$$\lambda_1=\lambda_2+\lambda_3$$
B
$$\lambda_2=\lambda_1+\lambda_3$$
C
$$\frac{1}{\lambda_1}=\frac{1}{\lambda_2}-\frac{1}{\lambda_3}$$
D
$$\frac{1}{\lambda_1}-\frac{1}{\lambda_2}=\frac{1}{\lambda_3}$$
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