MHT CET 2019 3rd May Morning Shift | Waves Question 106 | Physics

A sonometer wire is in unison with a tuning fork, when it is stretched by weight $w$ and the corresponding resonating length is $L_4$. If the weight is reduced to $\left(\frac{w}{4}\right)$, the corresponding resonating length becomes $L_2$. The ratio $\left(\frac{L_1}{L_2}\right)$ is

$4: 1$

$1: 4$

$1: 2$

$2: 1$

MHT CET 2019 3rd May Morning Shift

MCQ (Single Correct Answer)

-0

For formation of beats, two sound notes must have

different amplitudes and different frequencies

exactly equal frequencies only

exactly equal amplitudes only

nearly equal frequencies and equal amplitudes

MHT CET 2019 2nd May Evening Shift

MCQ (Single Correct Answer)

-0

A stretched string fixed at both ends has ' $m$ ' nodes, then the length of the string will be

$(m-1) \frac{\lambda}{2}$

$\frac{(m+1) \lambda}{2}$

$\frac{m \lambda}{2}$

$(m-2) \frac{\lambda}{2}$

MHT CET 2019 2nd May Evening Shift

MCQ (Single Correct Answer)

-0

A stretched wire of length 260 cm is set into vibrations. It is divided into three segments whose frequencies are in the ratio $2: 3: 4$. Their lengths must be

$80 \mathrm{~cm}, 60 \mathrm{~cm}, 120 \mathrm{~cm}$

$120 \mathrm{~cm}, 80 \mathrm{~cm}, 60 \mathrm{~cm}$

$60 \mathrm{~cm}, 80 \mathrm{~cm}, 120 \mathrm{~cm}$

$120 \mathrm{~cm}, 60 \mathrm{~cm}, 80 \mathrm{~cm}$

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