MHT CET 2024 15th May Evening Shift | Center of Mass and Collision Question 4 | Physics

A particle of mass m collides with another stationary particle of mass $M$. The particle $m$ stops just after collision. The coefficient of restitution is

$\frac{m}{M}$

$\frac{M-m}{M+m}$

$\frac{\mathrm{m}}{\mathrm{M}+\mathrm{m}}$

MHT CET 2024 15th May Evening Shift

MCQ (Single Correct Answer)

-0

1000 small balls, each weighing 1 gram, strike one square cm of area per second with a velocity $50 \mathrm{~m} / \mathrm{s}$ in a normal direction and rebound with the same velocity. The value of pressure on the surface will be

$10^7 \mathrm{~N} / \mathrm{m}^2$

$10^6 \mathrm{~N} / \mathrm{m}^2$

$5 \times 10^6 \mathrm{~N} / \mathrm{m}^2$

$2 \times 10^6 \mathrm{~N} / \mathrm{m}^2$

MHT CET 2024 11th May Evening Shift

MCQ (Single Correct Answer)

-0

A moving body with mass ' $\mathrm{m}_1$ ' strikes a stationary mass ' $\mathrm{m}_2$ '. What should be the ratio $\frac{m_1}{m_2}$ so as to decrease the velocity of first by (1.5) times the velocity after the collision?

$1: 25$

$1: 5$

$5: 1$

$25: 1$

MHT CET 2024 9th May Evening Shift

MCQ (Single Correct Answer)

-0

A metal rod of weight ' $W$ ' is supported by two parallel knife-edges A and B . The rod is in equilibrium in horizontal position. The distance ' between two knife-edges is ' $r$ '. The centre of mass of the rod is at a distance ' $x$ ' from $A$. The normal reaction on A is

$\frac{\mathrm{W} \cdot \mathrm{r}}{\mathrm{x}}$

$\frac{\mathrm{W} \cdot \mathrm{x}}{\mathrm{r}}$

$\mathrm{\frac{W \cdot(r-x)}{x}}$

$\mathrm{\frac{W \cdot(r-x)}{r}}$

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