MHT CET 2021 21th September Morning Shift | Center of Mass and Collision Question 9 | Physics

A particle of mass '$$m$$' collides with another stationary particle of mass '$$M$$'. A particle of mass '$$\mathrm{m}$$' stops just after collision. The coefficient of restitution is

$$\frac{M}{m}$$

$$\frac{m+M}{M}$$

$$\frac{M-m}{M+m}$$

$$\frac{\mathrm{m}}{\mathrm{M}}$$

MHT CET 2021 20th September Evening Shift

MCQ (Single Correct Answer)

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Two masses '$$m_{\mathrm{a}}$$' and '$$\mathrm{m}_{\mathrm{b}}$$' moving with velocities '$$v_{\mathrm{a}}$$' and '$$v_{\mathrm{b}}$$' opposite directions collide elastically. Alter the collision '$$m_a$$' and '$$m_b$$' move with velocities and '$$v_{\mathrm{b}}$$' and '$$v_a$$' respectively, then the ratio $$\mathrm{m_a:m_b}$$ is

$$\frac{v_a+v_b}{v_a-v_b}$$

$$\frac{1}{2}$$

$$\frac{v_a-v_b}{v_a+v_b}$$

MHT CET 2020 16th October Morning Shift

MCQ (Single Correct Answer)

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A bullet of mass $$m$$ moving with velocity $$v$$ is fired into a wooden block of mass $$M$$, If the bullet remains embedded in the block, the final velocity of the system is

$$\frac{m+M}{m}$$

$$\frac{M+m}{m v}$$

$$\frac{m v}{m+M}$$

$$\frac{v}{m(M+m)}$$

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