1
MHT CET 2025 20th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

A force acting on a body of mass 5 Kg is $(4 \hat{i}-2 \hat{j}+3 \hat{k}) \mathrm{N}$. If the body is initially at rest then the magnitude of its velocity at the end of 10 second in $\mathrm{m} / \mathrm{s}$ will be

A
$3 \sqrt{35}$
B
$2 \sqrt{29}$
C
$\sqrt{19}$
D
$3 \sqrt{23}$
2
MHT CET 2024 16th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A body travelling with uniform acceleration crosses two points A and B with velocities $20 \mathrm{~m} / \mathrm{s}$ and $30 \mathrm{~m} / \mathrm{s}$ respectively. The speed of the body at mid point of A and B is (nearly)

A
$25 \mathrm{~m} / \mathrm{s}$
B
$25.5 \mathrm{~m} / \mathrm{s}$
C
$24 \mathrm{~m} / \mathrm{s}$
D
$10 \sqrt{6} \mathrm{~m} / \mathrm{s}$
3
MHT CET 2024 16th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The co-ordinates of a moving particle at any time ' $t$ ' are given by $x=\alpha t^3$ and $y=\beta t^3$ where $\alpha$ and $\beta$ are constants. The speed of the particle at time ' $t$ ' is given by

A
$t \sqrt{\alpha^2+\beta^2}$
B
$3 t \sqrt{\alpha^2+\beta^2}$
C
$t^2 \sqrt{\alpha^2+\beta^2}$
D
$3 t^2 \sqrt{\alpha^2+\beta^2}$
4
MHT CET 2024 15th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A ball is released from the top of a tower of height Hm . It takes T second to reach the ground. The height of the ball from the ground after $\frac{T}{4}$ second is

A
$\frac{13 \mathrm{H}}{14}$
B
$\frac{15 \mathrm{H}}{16}$
C
$\frac{11 \mathrm{H}}{12}$
D
$\frac{9 \mathrm{H}}{10}$
MHT CET Subjects
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