MHT CET 2024 2nd May Morning Shift | Electromagnetic Induction Question 60 | Physics

A bicycle wheel of radius ' $R$ ' has ' $n$ ' spokes. It is rotating at the rate of ' $F$ ' r.p.m. perpendicular to the horizontal component of earth's magnetic field $\vec{B}$. The e.m.f. induced between the rim and the centre of the wheel is

$\frac{1}{2} \mathrm{~B} \pi \mathrm{FR}^2$

$\mathrm{B} \pi \mathrm{FR}^2$

$\frac{1}{\mathrm{n}} \mathrm{B} \pi \mathrm{FR}$

$B \pi \mathrm{FR}^2 n$

MHT CET 2023 14th May Evening Shift

MCQ (Single Correct Answer)

-0

A long solenoid has 1500 turns. When a current of $$3.5 \mathrm{~A}$$ flows through it, the magnetic flux linked with each turn of solenoid is $$2.8 \times 10^{-3}$$ weber. The self-inductance of solenoid is

1.2 H

2.4 H

3.6 H

6 H

MHT CET 2023 14th May Evening Shift

MCQ (Single Correct Answer)

-0

A coil having effective area A, is held with its plane normal to magnetic field of induction B. The magnetic induction is quickly reduced by $$25 \%$$ of its initial value in 2 second. Then the e.m.f. induced across the coil will be

$$\frac{\mathrm{AB}}{8}$$

$$\frac{\mathrm{AB}}{2}$$

$$\frac{3 \mathrm{AB}}{4}$$

$$\frac{3 \mathrm{AB}}{8}$$

MHT CET 2023 14th May Evening Shift

MCQ (Single Correct Answer)

-0

The self induction (L) produced by solenoid of length '$$l$$' having '$$\mathrm{N}$$' number of turns and cross sectional area '$$A$$' is given by the formula ($$\phi=$$ magnetic flux, $$\mu_0=$$ permeability of vacuum)

$$\mathrm{L}=\mathrm{N} \phi$$

$$\mathrm{L}=\mu_0 \mathrm{NAl}$$

$$\mathrm{L}=\frac{\mu_0 \mathrm{~N}^2 \mathrm{~A}}{l}$$

$$\mathrm{L}=\frac{\mu_0 \mathrm{NA}}{l}$$

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