1
GATE EE 2010
+2
-0.6
The two-port network P shown in the figure has ports 1 and 2, denoted by terminals (a, b) and (c, d), respectively. It has an impedance matrix Z with parameters denoted by zij. A 1 Ω resistor is connected in series with the network at port 1 as shown in the figure. The impedance matrix of the modified two-port network (shown as a dashed box) is
A
$$\begin{pmatrix}z_{11}+1&z_{12}+1\\z_{21}&z_{22}+1\end{pmatrix}$$
B
$$\begin{pmatrix}z_{11}+1&z_{12}\\z_{21}&z_{22}+1\end{pmatrix}$$
C
$$\begin{pmatrix}z_{11}+1&z_{12}\\z_{21}&z_{22}\end{pmatrix}$$
D
$$\begin{pmatrix}z_{11}+1&z_{12}\\z_{21}+1&z_{22}\end{pmatrix}$$
2
GATE EE 2006
+2
-0.6
The parameters of the circuit shown in the figure are
$${R_i} = 1\,\,M\,\Omega ,\,\,{R_0} = 10\,\Omega ,\,\,A = {10^6}\,\,V/V.$$ If $${V_i} = 1\,\,\mu V,\,\,$$ the output voltage, input impedance and output impedance respectively are
A
$$1\,V,\infty ,\,\,10\,\Omega$$
B
$$1\,V,0,\,\,10\,\Omega$$
C
$$1\,\,V,0,\,\,\infty$$
D
$$10\,\,V,\,\,\infty ,\,\,10\,\Omega$$
3
GATE EE 2005
+2
-0.6
Two networks are connected in cascade as shown in the Fig. With the usual notations the equivalent $$A,B,C$$ and $$D$$ constants are obtained. Given that, $$C$$ $$= 0.025\angle {45^ \circ },$$ the value of $${Z_2}$$ is
A
$$10\angle {30^ \circ }\Omega$$
B
$$40\angle - {45^ \circ }\,\,\Omega$$
C
$$1\,\,\Omega$$
D
$$0\,\,\Omega$$
4
GATE EE 2004
+2
-0.6
The $$Z$$ matrix of a $$2$$ $$-$$ port network is given by $$\left[ {\matrix{ {0.9} & {0.2} \cr {0.2} & {0.6} \cr } } \right].$$ The element $${Y_{22}}$$ vof the corresponding $$Y$$ matrix of the same network is given by
A
$$1.2$$
B
$$0.4$$
C
$$-0.4$$
D
$$1.8$$
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