1
GATE EE 2012
MCQ (Single Correct Answer)
+1
-0.3
The impedance looking into nodes 1 and 2 in the given circuit is GATE EE 2012 Electric Circuits - Network Theorems Question 30 English
A
50 Ω
B
100 Ω
C
5 kΩ
D
10.1 kΩ
2
GATE EE 2012
MCQ (Single Correct Answer)
+1
-0.3
In the circuit shown below, the current through the inductor is GATE EE 2012 Electric Circuits - Network Theorems Question 29 English
A
$$\frac2{1+\mathrm j}\;\mathrm A$$
B
$$\frac{-1}{1+\mathrm j}\;\mathrm A$$
C
$$\frac1{1+\mathrm j}\;\mathrm A$$
D
0 A
3
GATE EE 2011
MCQ (Single Correct Answer)
+1
-0.3
In the circuit given below, the value of R required for the transfer of maximum power to the load having a resistance of 3 Ω is GATE EE 2011 Electric Circuits - Network Theorems Question 31 English
A
zero
B
3 Ω
C
6 Ω
D
infinity
4
GATE EE 2006
MCQ (Single Correct Answer)
+1
-0.3
In the figure the current source is $$1\,\,\angle \,0\,A,$$ $$R = \,1\,\,\Omega ,$$ the impedances are $${Z_C} = - j\,\,\Omega ,$$ and $${Z_L} = 2\,j\,\,\Omega .$$ The Thevenin equivalent looking into the circuit across $$X-Y$$ is. GATE EE 2006 Electric Circuits - Network Theorems Question 11 English
A
$$\sqrt 2 \,\,\angle 0,\,\,V,\,\,\left( {1 + 2j} \right)\,\,\Omega $$
B
$$2\,\,\angle {45^ \circ },\,\,V,\,\,\left( {1 - 2j} \right)\,\,\Omega $$
C
$$2\,\,\angle {45^ \circ },\,\,V,\,\,\left( {1 + j} \right)\,\,\Omega $$
D
$$\sqrt 2 \,\,\angle {45^ \circ },\,\,V,\,\,\left( {1 + j} \right)\,\,\Omega $$
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