1
GATE EE 2005
+2
-0.6
The circuit shown in the Fig. is in steady state, when the switch is closed at $$t=0.$$ Assuming that the inductance is ideal, the current through the inductor at $$t = {0^ + }$$ equals
A
$$0$$ $$A$$
B
$$0.5$$ $$A$$
C
$$1$$ $$A$$
D
$$2$$ $$A$$
2
GATE EE 2005
+2
-0.6
A coil of inductance $$10$$ $$H$$ resistance $$40\,\,\Omega$$ is connected as shown in Fig. After the switch $$S$$ has been in connection with point $$1$$ for a very long time, it is moved to point $$2$$ at $$t = 0.$$

For the value of $$R$$ obtained in the above question, the time taken for $$95\%$$ of the stored energy to be dissipated is close to

A
$$0.10$$ $$sec$$
B
$$0.15$$ $$sec$$
C
$$0.50$$ $$sec$$
D
$$1.0$$ $$sec$$
3
GATE EE 2004
+2
-0.6
In figure, the capacitor initially has a charge of $$10$$ Coulomb. The current in the circuit one second after the switch $$S$$ is closed will be
A
$$14.7$$ $$A$$
B
$$18.5$$ $$A$$
C
$$40.0$$ $$A$$
D
$$50.0$$ $$A$$
4
GATE EE 2003
+2
-0.6
In the circuit shown in Fig., the switch $$S$$ is closed at time $$t=0$$. The voltage across the inductance at $$t = {0^ + },$$ is
A
$$2$$ $$V$$
B
$$4$$ $$V$$
C
$$-6$$ $$V$$
D
$$8$$ $$V$$
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