A single-phase voltage source $v_s=325 \sin (2 \pi 50 t) \vee$ delivers a current, $i=12 \sin (2 \pi 50 t) +9 \sin (2 \pi 50 t)$ A to a load.

The load power factor, correct up to two decimal places, is

The input voltage $v(t)$ and current $i(t)$ of a converter are given by, $v(t)=300 \sin (\omega t) \mathrm{V}$

$$ i(t)=10 \sin \left(\omega t-\frac{\pi}{6}\right)+2 \sin \left(3 \omega t+\frac{\pi}{6}\right)+\sin \left(5 \omega t+\frac{\pi}{2}\right) A $$

where, $\omega=2 \pi \times 50 \mathrm{rad} / \mathrm{s}$. The input power factor of the converter is closest to

The value of parameters of the circuit shown in the figure are

$${R_1} = 2\Omega ,{R_2} = 2\Omega ,{R_3} = 3\Omega ,L = 10$$ mH, $$C = 100$$ $$\mu$$F

For time t < 0, the circuit is at steady state with the switch 'K' in closed condition. If the switch is opened at t = 0, the value of the voltage across the inductor (V$$_L$$) at t = 0$$^+$$ in Volts is ___________ (Round off to 1 decimal place).

An inductor having a Q-factor of 60 is connected in series with a capacitor having a Q-factor of 240. The overall Q-factor of the circuit is ________. (round off to nearest integer).