1
GATE EE 2007
+2
-0.6
In the circuit shown in Fig. switch $$S{w_1}$$ is initially CLOSED and $$S{w_2}$$ is OPEN. The inductor $$L$$ carries a current of $$10$$ $$A$$ and the capacitor is charged to $$10$$ $$V$$ with polarities as indicated. $$S{w_2}$$ in initially CLOSED at $$t = {0^ - }$$ and $$S{w_1}$$ is OPENED at $$t=0.$$ The current through $$C$$ and the voltage across $$L$$ at $$t = {0^ + }$$ is
A
$$55$$ $$A,$$ $$4.5$$ $$V$$
B
$$5.5$$ $$A,$$ $$45$$ $$V$$
C
$$45$$ $$A,$$ $$5.5$$ $$V$$
D
$$4.5$$ $$A,$$ $$55$$ $$V$$
2
GATE EE 2006
+2
-0.6
An ideal capacitor is charged to a voltage $${V_0}$$ and connected at $$t=0$$ across an ideal inductor $$L.$$ (The circuit now consists of a capacitor and inductor alone). If we let $${\omega _0} = 1/\sqrt {LC} ,$$ the voltage across the capacitor at time $$t>0$$ is given by
A
$${V_0}$$
B
$${V_0}\cos \left( {{\omega _0}t} \right)$$
C
$${V_0}son\left( {{\omega _0}t} \right)$$
D
$${V_0}{e^{ - {\omega _0}t}}\cos \left( {{\omega _0}t} \right)$$
3
GATE EE 2005
+2
-0.6
A coil of inductance $$10$$ $$H$$ resistance $$40\,\,\Omega$$ is connected as shown in Fig. After the switch $$S$$ has been in connection with point $$1$$ for a very long time, it is moved to point $$2$$ at $$t = 0.$$

For the value of $$R$$ obtained in the above question, the time taken for $$95\%$$ of the stored energy to be dissipated is close to

A
$$0.10$$ $$sec$$
B
$$0.15$$ $$sec$$
C
$$0.50$$ $$sec$$
D
$$1.0$$ $$sec$$
4
GATE EE 2005
+2
-0.6
A coil of inductance $$10$$ $$H$$ resistance $$40\,\,\Omega$$ is connected as shown in Fig. After the switch $$S$$ has been in connection with point $$1$$ for a very long time, it is moved to point $$2$$ at $$t = 0.$$

If, at $$t = {0^ + }$$, the voltage across the coil is $$120$$ $$V,$$ the value of resistance $$R$$ is

A
$$0$$ $$\Omega$$
B
$$20$$ $$\Omega$$
C
$$40$$ $$\Omega$$
D
$$60$$ $$\Omega$$
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