1
GATE EE 2003
MCQ (Single Correct Answer)
+1
-0.3
In the circuit of figure shown, assume that the transistor has $${h_{fe}} = 99$$ and $${V_{BE}} = 0.7V.$$
The value of collector current $${{\rm I}_C}$$ of the transistor is approximately GATE EE 2003 Analog Electronics - Bjt and Mosfet Biasing Question 33 English
A
$$\left[ {3.3/3.3} \right]\,mA$$
B
$$\left[ {3.3/\left( {3.3 + 0.33} \right)} \right]\,mA$$
C
$$\left[ {3.3/33} \right]\,mA$$
D
$$\left[ {3.3/\left( {33 + 33} \right)} \right]\,mA$$
2
GATE EE 2003
MCQ (Single Correct Answer)
+2
-0.6
A voltage signal $$\,10\,\,\sin \,\omega t\,\,$$ is applied to the circuit with ideal diodes, as shown in figure. The maximum and minimum values of the output waveform of the circuit are respectively GATE EE 2003 Analog Electronics - Diode Circuits and Applications Question 18 English
A
$$+10V$$ and $$-10V$$
B
$$+4V$$ and $$-4V$$
C
$$+7V$$ and $$-4V$$
D
$$+4V$$ and $$-7V$$
3
GATE EE 2003
MCQ (Single Correct Answer)
+1
-0.3
A lead compensator used for a closed loop controller has the following transfer function $${\textstyle{{K\left( {1 + {s \over a}} \right)} \over {\left( {1 + {s \over b}} \right)}}}\,\,\,$$ For such a lead compensator
A
$$a < b$$
B
$$b < a$$
C
$$a > Kb$$
D
$$a < Kb$$
4
GATE EE 2003
MCQ (Single Correct Answer)
+2
-0.6
The following equation defines a separately exited $$dc$$ motor in the form of a differential equation $${{{d^2}\omega } \over {d{t^2}}} + {{B\,d\omega } \over {j\,\,dt}} + {{{K^2}} \over {LJ}}\omega = {K \over {LJ}}{V_a}$$

The above equation may be organized in the state space form as follows
$$\left( {\matrix{ {{{{d^2}\omega } \over {d{t^2}}}} \cr {{{d\omega } \over {dt}}} \cr } } \right) = P\left( {\matrix{ {{{d\omega } \over {dt}}} \cr \omega \cr } } \right) + Q{V_a}$$

where the $$P$$ matrix is given by

A
$$\left( {\matrix{ { - {B \over J}} & { - {{{K^2}} \over {LJ}}} \cr 1 & 0 \cr } } \right)$$
B
$$\left( {\matrix{ { - {{{K^2}} \over {LJ}}} & { - {B \over J}} \cr 0 & 1 \cr } } \right)$$
C
$$\left( {\matrix{ 0 & 1 \cr { - {{{K^2}} \over {LJ}}} & { - {B \over J}} \cr } } \right)$$
D
$$\left( {\matrix{ 1 & 0 \cr { - {B \over J}} & { - {{{K^2}} \over {LJ}}} \cr } } \right)$$
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