1
GATE EE 2003
MCQ (Single Correct Answer)
+2
-0.6
The asymptotic Bode plot of the transfer function $${K \over {1 + {s \over a}}}$$. The error in phase angle and $$dB$$ gain at a frequency of $$\omega = 0.5a$$ are respectively GATE EE 2003 Control Systems - Polar Nyquist and Bode Plot Question 27 English
A
$${4.9^0},\,0.97\,dB$$
B
$${5.7^0},\,3\,dB$$
C
$${4.9^0},\,3\,dB$$
D
$${5.7^0},\,0.97\,dB$$
2
GATE EE 2003
MCQ (Single Correct Answer)
+1
-0.3
A lead compensator used for a closed loop controller has the following transfer function $${\textstyle{{K\left( {1 + {s \over a}} \right)} \over {\left( {1 + {s \over b}} \right)}}}\,\,\,$$ For such a lead compensator
A
$$a < b$$
B
$$b < a$$
C
$$a > Kb$$
D
$$a < Kb$$
3
GATE EE 2003
MCQ (Single Correct Answer)
+1
-0.3
A second order system starts with an initial condition of $$\left( {\matrix{ 2 \cr 3 \cr } } \right)$$ without any external input. The state transition matrix for the system is given by $$\left( {\matrix{ {{e^{ - 2t}}} & 0 \cr 0 & {{e^{ - t}}} \cr } } \right).$$ The state of the system at the end of $$1$$ second is given by.
A
$$\,\,\left( {\matrix{ {0.271} \cr {1.100} \cr } } \right)$$
B
$$\left( {\matrix{ {0.135} \cr {0.368} \cr } } \right)$$
C
$$\left( {\matrix{ {0.271} \cr {0.736} \cr } } \right)$$
D
$$\left( {\matrix{ {0.135} \cr {1.100} \cr } } \right)$$
4
GATE EE 2003
MCQ (Single Correct Answer)
+2
-0.6
The following equation defines a separately exited $$dc$$ motor in the form of a differential equation $${{{d^2}\omega } \over {d{t^2}}} + {{B\,d\omega } \over {j\,\,dt}} + {{{K^2}} \over {LJ}}\omega = {K \over {LJ}}{V_a}$$

The above equation may be organized in the state space form as follows
$$\left( {\matrix{ {{{{d^2}\omega } \over {d{t^2}}}} \cr {{{d\omega } \over {dt}}} \cr } } \right) = P\left( {\matrix{ {{{d\omega } \over {dt}}} \cr \omega \cr } } \right) + Q{V_a}$$

where the $$P$$ matrix is given by

A
$$\left( {\matrix{ { - {B \over J}} & { - {{{K^2}} \over {LJ}}} \cr 1 & 0 \cr } } \right)$$
B
$$\left( {\matrix{ { - {{{K^2}} \over {LJ}}} & { - {B \over J}} \cr 0 & 1 \cr } } \right)$$
C
$$\left( {\matrix{ 0 & 1 \cr { - {{{K^2}} \over {LJ}}} & { - {B \over J}} \cr } } \right)$$
D
$$\left( {\matrix{ 1 & 0 \cr { - {B \over J}} & { - {{{K^2}} \over {LJ}}} \cr } } \right)$$
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