1
MHT CET 2021 23rd September Evening Shift
MCQ (Single Correct Answer)
+2
-0

The area of the triangle $$\mathrm{ABC}$$ is $$10 \sqrt{3} \mathrm{~cm}^2$$, angle $$\mathrm{B}$$ is $$60^{\circ}$$ and its perimeter is $$20 \mathrm{~cm}$$, then $$\ell(\mathrm{AC})=$$

A
10 cm
B
8 cm
C
5 cm
D
7 cm
2
MHT CET 2021 23th September Morning Shift
MCQ (Single Correct Answer)
+2
-0

In a triangle $$\mathrm{ABC}$$, with usual notations $$\mathrm{a}=2, \mathrm{~b}=3, \mathrm{c}=5$$, then $$\frac{\cos \mathrm{A}}{\mathrm{a}}+\frac{\cos \mathrm{B}}{\mathrm{b}}+\frac{\cos \mathrm{C}}{\mathrm{c}}=$$

A
$$\frac{19}{30}$$
B
$$\frac{19}{60}$$
C
$$\frac{23}{60}$$
D
$$\frac{38}{35}$$
3
MHT CET 2021 22th September Evening Shift
MCQ (Single Correct Answer)
+2
-0

In $$\Delta ABC$$, with usual notations $$\mathrm{\frac{b\sin B-c\sin C}{\sin(B-C)}}=$$

A
b
B
C
C
a
D
a + b + c
4
MHT CET 2021 22th September Evening Shift
MCQ (Single Correct Answer)
+2
-0

With usual notations, in any $$\triangle A B C$$, if $$a\cos B=b \cos A$$, then the triangle is

A
an isosceles triangle
B
an equilateral triangle
C
a right angled triangle
D
a scalene triangle
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