MHT CET 2021 21th September Morning Shift | Electromagnetic Induction Question 39 | Physics

A wire of length '$$L$$'; having resistance '$$R$$' falls from a height '$$\ell$$' in earth's horizontal magnetic field '$$B$$'. The current through the wire is ( $$\mathrm{g}=$$ acceleration due to gravity)

$$\frac{\mathrm{BL} \sqrt{2 \mathrm{~g} \ell}}{\mathrm{R}}$$

$$\frac{\mathrm{BL} \sqrt{2 \mathrm{~g} \ell}}{\mathrm{R}^2}$$

$$\frac{2 \mathrm{BLg} \ell}{\mathrm{R}^2}$$

$$\frac{\mathrm{B}^2 \mathrm{~L}^2}{\mathrm{R}}$$

MHT CET 2021 21th September Morning Shift

MCQ (Single Correct Answer)

-0

A coil of radius '$$\mathrm{r}$$' is placed on another coil (whose radius is '$$\mathrm{R}$$' and current through it is changing) so that their centres coincide. ( $$R > r$$ ). If both coplanar, then the mutual inductance between them is proportional to

$$\frac{R}{r^2}$$

$$\frac{r}{R}$$

$$\frac{R}{r}$$

$$\frac{r^2}{R}$$

MHT CET 2021 20th September Evening Shift

MCQ (Single Correct Answer)

-0

A metal wire of length $$2500 \mathrm{~m}$$ is kept in east-west direction, at a height of $$10 \mathrm{~m}$$ from the ground. If it falls freely on the ground then the current induced in the wire is (Resistance of wire $$=25 \sqrt{2} \Omega, \mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2$$ and Earth's horizontal component of magnetic field $$\left.\mathrm{B}_{\mathrm{H}}=2 \times 10^{-5} \mathrm{~T}\right)$$

0.2 A

0.02 A

0.01 A

2 A

MHT CET 2021 20th September Morning Shift

MCQ (Single Correct Answer)

-0

Two conducting wire loops are concentric and lie in the same plane. The current in the outer loop is clockwise and increasing with time. The induced current in the inner loop is

clockwise

anticlockwise

in a direction which depends on the ratio of the loop radii.

zero

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