The input voltage given to a converter is
$${V_i} = 100\sqrt 2 \,\,\,\sin \,\,\,\left( {100\pi t} \right)\,\,V$$
The current drawn by the converter is
$${i_i} = 10\sqrt 2 \,\,\,\sin \,\,\,\left( {100\pi t - {\pi \over 3}} \right)\,\, + 5\sqrt 2 $$
$$\sin \left( {300\pi t + {\pi \over 4}} \right)\,\, + \,\,2\sqrt 2 \,\,\sin \left( {500\pi t - {\pi \over 6}} \right)A$$

The active power drawn by the converter is

The circuit shows an ideal diode connected to a pure inductor and is connected to a purely sinusoidal $$50$$ $$Hz$$ voltage source. Under ideal condition the current waveform through the indicator will look like

A single - phase half controlled converter shown in the figure feeding power to highly inductive load. The converter is operating at a firing angle of $${60^ \circ }.$$

If the firing pulses are suddenly removed, the steady state voltage $$\left( {{V_0}} \right)$$ waveform of the converter will become

A single phase fully controlled converter bridge is used for electrical braking of a separately excited $$dc$$ motor. The $$dc$$ motor load is represented by an equivalent circuit as shown in the figure.

Assume that the load inductance is sufficient to ensure continuous and ripple free load current. The firing angle of the bridge for a load current of $${{\rm I}_0} = 10\,\,A$$ will be