$\frac{d}{d t}\left[\begin{array}{l}v \\ i\end{array}\right]=\left[\begin{array}{ll}-4 & -4 \\ -2 & -4\end{array}\right]\left[\begin{array}{l}v \\ i\end{array}\right]+\left[\begin{array}{ll}4 & 0 \\ 0 & 4\end{array}\right]\left[\begin{array}{l}i_1 \\ i_2\end{array}\right]$

$\frac{d}{d t}\left[\begin{array}{c}v \\ i\end{array}\right]=\left[\begin{array}{cc}-4 & 4 \\ -2 & -4\end{array}\right]\left[\begin{array}{c}v \\ i\end{array}\right]+\left[\begin{array}{ll}0 & 4 \\ 4 & 0\end{array}\right]\left[\begin{array}{l}i_1 \\ i_2\end{array}\right]$

$\frac{d}{d t}\left[\begin{array}{l}v \\ i\end{array}\right]=\left[\begin{array}{cc}4 & -4 \\ -2 & -4\end{array}\right]\left[\begin{array}{l}v \\ i\end{array}\right]+\left[\begin{array}{ll}0 & 4 \\ 4 & 4\end{array}\right]\left[\begin{array}{l}i_1 \\ i_2\end{array}\right]$

$\frac{d}{d t}\left[\begin{array}{l}v \\ i\end{array}\right]=\left[\begin{array}{cc}-4 & -4 \\ -2 & 4\end{array}\right]\left[\begin{array}{l}v \\ i\end{array}\right]+\left[\begin{array}{ll}4 & 4 \\ 4 & 0\end{array}\right]\left[\begin{array}{l}i_1 \\ i_2\end{array}\right]$

$2.38 \angle-96.37^{\circ} \mathrm{A}$.

0 A .

$2.38 \angle-23.63^{\circ} \mathrm{A}$.

$2.38 \angle 143.63^{\circ} \mathrm{A}$.

unit step signal $u[n]$.

0 for all $n$.

unit impulse signal $\delta[n]$.

1 for all $n$.