GATE ECE 2020 | GATE ECE Year Wise Previous Years Questions

GATE ECE 2020

MCQ (Single Correct Answer)

-0.33

$$ \text { In the circuit shown below, the Thevenin voltage } V_{\text {th }} \text { is } $$

GATE ECE 2020 Network Theory - Network Theorems Question 4 English

4.5 V

3.6 V

2.4 V

2.8 V

GATE ECE 2020

Numerical

-0

The current in the RL - circuit shown below is $i(t)=10 \cos (5 t-\pi / 4) \mathrm{A}$. The value of the inductor (rounded off to two decimal places) is $\_\_\_\_$ H.

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GATE ECE 2020

Numerical

-0

In the circuit shown below, all the components are ideal and the input voltage is sinusoidal. The magnitude of the steady - state output $V_0$ (rounded off to two decimal places) is $\_\_\_\_$ V.

GATE ECE 2020 Network Theory - Sinusoidal Steady State Response Question 5 English

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GATE ECE 2020

MCQ (Single Correct Answer)

-0.67

$$ \text { For the given circuit, which one of the following is the correct state equation? } $$

GATE ECE 2020 Network Theory - State Equations For Networks Question 1 English

$\frac{d}{d t}\left[\begin{array}{l}v \\ i\end{array}\right]=\left[\begin{array}{ll}-4 & -4 \\ -2 & -4\end{array}\right]\left[\begin{array}{l}v \\ i\end{array}\right]+\left[\begin{array}{ll}4 & 0 \\ 0 & 4\end{array}\right]\left[\begin{array}{l}i_1 \\ i_2\end{array}\right]$

$\frac{d}{d t}\left[\begin{array}{c}v \\ i\end{array}\right]=\left[\begin{array}{cc}-4 & 4 \\ -2 & -4\end{array}\right]\left[\begin{array}{c}v \\ i\end{array}\right]+\left[\begin{array}{ll}0 & 4 \\ 4 & 0\end{array}\right]\left[\begin{array}{l}i_1 \\ i_2\end{array}\right]$

$\frac{d}{d t}\left[\begin{array}{l}v \\ i\end{array}\right]=\left[\begin{array}{cc}4 & -4 \\ -2 & -4\end{array}\right]\left[\begin{array}{l}v \\ i\end{array}\right]+\left[\begin{array}{ll}0 & 4 \\ 4 & 4\end{array}\right]\left[\begin{array}{l}i_1 \\ i_2\end{array}\right]$

$\frac{d}{d t}\left[\begin{array}{l}v \\ i\end{array}\right]=\left[\begin{array}{cc}-4 & -4 \\ -2 & 4\end{array}\right]\left[\begin{array}{l}v \\ i\end{array}\right]+\left[\begin{array}{ll}4 & 4 \\ 4 & 0\end{array}\right]\left[\begin{array}{l}i_1 \\ i_2\end{array}\right]$

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