1
GATE ECE 2012
MCQ (Single Correct Answer)
+1
-0.3
The power spectral density of a real process X(t) for positive frequencies is shown below. The value of $$E\,\left[ {{X^2}\,(t)} \right]$$ and $$E\,\left[ {X\,(t)} \right]$$, respectively, are GATE ECE 2012 Communications - Random Signals and Noise Question 12 English
A
$$6000/\,\pi ,\,0$$
B
$$6400/\,\pi ,\,0$$
C
$$\,6400/\,\pi ,\,\,20\,\left( {\pi \sqrt 2 } \right)$$
D
$$\,6000/\,\pi ,\,\,20\,\left( {\pi \sqrt 2 } \right)$$
2
GATE ECE 2012
MCQ (Single Correct Answer)
+2
-0.6
A BPSK scheme operating over an AWGN channel with noise power spectral density of N02, uses equi-probable signals $$${s_1}\left( t \right) = \sqrt {{{2E} \over T}\,\sin \left( {{\omega _c}t} \right)} $$$
and $$${s_2}\left( t \right) = - \sqrt {{{2E} \over T}\,\sin \left( {{\omega _c}t} \right)} $$$

over the symbol interval, $$(0, T)$$. If the local oscillator in a coherent receiver is ahead in phase by 450 with respect to the received signal, the probability of error in the resulting system is

A
$$Q\left( {\sqrt {{{2E} \over {{N_0}}}} } \right)$$
B
$$Q\left( {\sqrt {{{E} \over {{N_0}}}} } \right)$$
C
$$Q\left( {\sqrt {{{E} \over {{2N_0}}}} } \right)$$
D
$$Q\left( {\sqrt {{{E} \over {{4N_0}}}} } \right)$$
3
GATE ECE 2012
MCQ (Single Correct Answer)
+2
-0.6
A binary symmetric channel (BSC) has a transition probability of 1/8. If the binary transmit symbol X is such that P(X =0) = 9/10, then the probability of error for an optimum receiver will be
A
7/80
B
63/80
C
9/10
D
1/10
4
GATE ECE 2012
MCQ (Single Correct Answer)
+2
-0.6
The feedback system shown below oscillates at 2 rad/s when GATE ECE 2012 Control Systems - Stability Question 11 English
A
K = 2 and a = 0.75
B
K = 3 and a = 0.75
C
K = 4 and a = 0.5
D
K = 2 and a = 0.5
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